#include <stdio.h>
void main()
{
double r,area;
printf("");
scanf("%lf",&r);
area=3.1415926*r*r;
printf("%lf\n",area);
}
285-56
2.1758.563-56.1254
‘a’ 9’
15


max=10 10
max
#include <stdio.h>
void main()
{
Int x,y,z;
X=5;
Y=6;
Z=x+y;
Printf(―%d‖,z);
}
areas_name _namesum4 4letter
8(turbo C)
student_name student_code
nameNAME
C
includeifintfloat32
lo
num1
int area
Void a3_b3 for 2a define
_123 -abc do word if
case sigeof _sum 3Dmax
#include <stdio.h>
void main()
{
int a;
int b;
int c;/*a,b,cint a,b c;-*/
a=10;
b=20;/*a,b*/
c=a*b;
printf("c=%d\n",c);
}
int num
Alan‖ abc‖
16 2 -32768 32767
123220-232
float num;
6-7
32 4
23.0556.532
float
,double num;
13-14
64 8
23.34232324
-32768 ≤x≤32767 2
-2147483648 ≤x
2147483647
4
-3.402823E38 ≤x
-1.401298E-45,
1.401298E-45 ≤x
3.402823E38
4
6
char
char gender;
gender=?m';
81
'a''m''$''%''1''5'
#include <stdio.h>
void main()
{
char ch1,ch2;
ch1='a';
ch2='b';
printf("%c\n",ch1-32);
printf("%c\n",ch2+1);
}
2-1
char 8 128 127
unsigned 8 0 255
signed char 8 -128 127
int 16 -32,768 32,767
unsigned int 16 0 65,535
signed int 16 int
short int 16 int
unsigned short
int
8 0 65,535
Void main ()
{
char abc; /*abc */
int xyz; /*xyz */
float length; /*length */
double area; /*area */
long liteyrs; /*liteyrs */
short arm; /*arm */
}
sum_1
sum_2
sum_3
sum_4
5_sum
Int sum_1=5;
Float sum_2=3.0;
Char sum_3=?a‘;
Int sum_1;
Char sum_3;
Sum_1=10;
Sum_3=?b‘;
()
- +
++ -
-- *
%
/
“/”
#include <stdio.h>
void main()
{
int i=5;
printf("%d\n",i/3);
printf("%f\n",5/3.0);
}
-*/%+-
,-();.
()
,
4 + 3*-6/2-5+5
4+3*[-6]/2-5+5
4+[-18/2]-5+5
[4+-9]-5+5
[-5]-5+5
-5
int a=1,b=2,c=3;float d=4; C
A) a/(b+c)*d ; B)a/(b+c)*1/d; C)a/(c+b)/d;
D)a/d/(b+c)
3.6/6+1/2+55%10
dcb
a
*)(?
++—
++—+1-1
a++++aa=a+1;
A----aa=a-1
++a--a
a++a—
++a—aa++a—
++—
++
A=1
A++,++A A2
BA B1A2
BA B=2A=2;
++—
a=3c=2
1.bac
b32
b1a3+14
2.ba)c
a=3+1=4;
b=4-2
b=2;
a3c2
1.b=a--c b= ;a=;
2.b(--a)-c b= ;a=;
3b=(++a)-(--a) b=?;a=?;
4b(++a)-(--a)a-- b=?;a=?;
a(a5)
(1)a+=a;
(2)a=(a--)+3;
(3)a=a+=2*3;
(4)a+=a-=a*=a=6
(5)(int a=5,b=3;float x=2.5,y=3.7;)
a) (x*a++)-y/2.0+a%b
b)(x*(++a))-y/2+a/b;