Chapter 12
Infrared Spectroscopy and
Mass Spectrometry
Jo Blackburn
Richland College,Dallas,TX
Dallas County Community College District
2003,Prentice Hall
Organic Chemistry,5th Edition
L,G,Wade,Jr.
Chapter 12 2
Introduction
Spectroscopy is an analytical technique
which helps determine structure.
It destroys little or no sample.
The amount of light absorbed by the
sample is measured as wavelength is
varied,
=>
Chapter 12 3
Types of Spectroscopy
Infrared (IR) spectroscopy measures the bond
vibration frequencies in a molecule and is used
to determine the functional group.
Mass spectrometry (MS) fragments the molecule
and measures the masses.
Nuclear magnetic resonance (NMR)
spectroscopy detects signals from hydrogen
atoms and can be used to distinguish isomers,
Ultraviolet (UV) spectroscopy uses electron
transitions to determine bonding patterns,=>
Chapter 12 4
Electromagnetic
Spectrum
Examples,X rays,microwaves,radio
waves,visible light,IR,and UV.
Frequency and wavelength are
inversely proportional.
c = ln,where c is the speed of light.
Energy per photon = hn,where h is
Planck’s constant,=>
Chapter 12 5
The Spectrum and
Molecular Effects
=>
=>
Chapter 12 6
The IR Region
Just below red in the visible region.
Wavelengths usually 2.5-25 mm.
More common units are wavenumbers,
or cm-1,the reciprocal of the wavelength
in centimeters.
Wavenumbers are proportional to
frequency and energy,=>
Chapter 12 7
Molecular Vibrations
Covalent bonds vibrate at only certain
allowable frequencies.
=>
Chapter 12 8
Stretching Frequencies
Frequency decreases with increasing
atomic weight.
Frequency increases with increasing
bond energy,=>
Chapter 12 9
Vibrational Modes
Nonlinear molecule with n atoms usually has
3n - 6 fundamental vibrational modes.
=>
Chapter 12 10
Fingerprint of Molecule
Whole-molecule vibrations and bending
vibrations are also quantitized.
No two molecules will give exactly the
same IR spectrum (except enantiomers).
Simple stretching,1600-3500 cm-1.
Complex vibrations,600-1400 cm-1,
called the,fingerprint region.”
=>
Chapter 12 11
IR-Active and Inactive
A polar bond is usually IR-active.
A nonpolar bond in a symmetrical
molecule will absorb weakly or not at all.
=>
Chapter 12 12
An Infrared
Spectrometer
=>
Chapter 12 13
FT-IR Spectrometer
Uses an interferometer.
Has better sensitivity.
Less energy is needed from source.
Completes a scan in 1-2 seconds.
Takes several scans and averages them.
Has a laser beam that keeps the
instrument accurately calibrated,=>
Chapter 12 14
Carbon-Carbon
Bond Stretching
Stronger bonds absorb at higher
frequencies:
C-C 1200 cm-1
C=C 1660 cm-1
C?C 2200 cm-1 (weak or absent if internal)
Conjugation lowers the frequency:
isolated C=C 1640-1680 cm-1
conjugated C=C 1620-1640 cm-1
aromatic C=C approx,1600 cm-1 =>
Chapter 12 15
Carbon-Hydrogen
Stretching
Bonds with more s character absorb at a
higher frequency.
sp3 C-H,just below 3000 cm-1 (to the right)
sp2 C-H,just above 3000 cm-1 (to the left)
sp C-H,at 3300 cm-1
=>
Chapter 12 16
An Alkane IR Spectrum
=>
Chapter 12 17
An Alkene IR Spectrum
=>
Chapter 12 18
An Alkyne IR Spectrum
=>
Chapter 12 19
O-H and N-H
Stretching
Both of these occur around 3300 cm-1,
but they look different.
Alcohol O-H,broad with rounded tip.
Secondary amine (R2NH),broad with one
sharp spike.
Primary amine (RNH2),broad with two
sharp spikes.
No signal for a tertiary amine (R3N) =>
Chapter 12 20
An Alcohol IR
Spectrum
=>
Chapter 12 21
An Amine
IR Spectrum
=>
Chapter 12 22
Carbonyl Stretching
The C=O bond of simple ketones,
aldehydes,and carboxylic acids absorb
around 1710 cm-1.
Usually,it’s the strongest IR signal.
Carboxylic acids will have O-H also.
Aldehydes have two C-H signals around
2700 and 2800 cm-1,
=>
Chapter 12 23
A Ketone
IR Spectrum
=>
Chapter 12 24
An Aldehyde
IR Spectrum
=>
Chapter 12 25
O-H Stretch of a
Carboxylic Acid
This O-H absorbs broadly,2500-3500 cm-1,
due to strong hydrogen bonding.
=>
Chapter 12 26
Variations in
C=O Absorption
Conjugation of C=O with C=C lowers the
stretching frequency to ~1680 cm-1.
The C=O group of an amide absorbs at an
even lower frequency,1640-1680 cm-1.
The C=O of an ester absorbs at a higher
frequency,~1730-1740 cm-1.
Carbonyl groups in small rings (5 C’s or
less) absorb at an even higher frequency,=>
Chapter 12 27
An Amide
IR Spectrum
=>
Chapter 12 28
Carbon - Nitrogen
Stretching
C - N absorbs around 1200 cm-1.
C = N absorbs around 1660 cm-1 and is
much stronger than the C = C
absorption in the same region.
C? N absorbs strongly just above 2200
cm-1,The alkyne C? C signal is much
weaker and is just below 2200 cm-1,
=>
Chapter 12 29
A Nitrile
IR Spectrum
=>
Chapter 12 30
Summary of IR
Absorptions
=>=>
Chapter 12 31
Strengths and Limitations
IR alone cannot determine a structure.
Some signals may be ambiguous.
The functional group is usually indicated.
The absence of a signal is definite proof
that the functional group is absent.
Correspondence with a known sample’s
IR spectrum confirms the identity of the
compound,=>
Chapter 12 32
Mass Spectrometry
Molecular weight can be obtained from a
very small sample.
It does not involve the absorption or
emission of light.
A beam of high-energy electrons breaks
the molecule apart.
The masses of the fragments and their
relative abundance reveal information
about the structure of the molecule,=>
Chapter 12 33
Electron Impact Ionization
A high-energy electron can dislodge an
electron from a bond,creating a radical
cation (a positive ion with an unpaired e-).
e - + H C
H
H
C
H
H
H
H C
H
H
C
H
H
H
H C
H
H
C
H
H
+ H
H C
H
H
C
H
H
H
+=>
Chapter 12 34
Separation of Ions
Only the cations are deflected by the
magnetic field.
Amount of deflection depends on m/z.
The detector signal is proportional to the
number of ions hitting it.
By varying the magnetic field,ions of all
masses are collected and counted,=>
Chapter 12 35
Mass Spectrometer
=>
Chapter 12 36
The Mass Spectrum
Masses are graphed or tabulated according to
their relative abundance.
=>
Chapter 12 37
The GC-MS
=>
A mixture of compounds is separated
by gas chromatography,then identified
by mass spectrometry.
Chapter 12 38
High Resolution MS
Masses measured to 1 part in 20,000.
A molecule with mass of 44 could be
C3H8,C2H4O,CO2,or CN2H4.
If a more exact mass is 44.029,pick the
correct structure from the table:
C3H8 C2H4O CO2 CN2H4
44.06260 44.02620 43.98983 44.03740
=>
Chapter 12 39
Molecules with
Heteroatoms
Isotopes,present in their usual abundance.
Hydrocarbons contain 1.1% C-13,so there
will be a small M+1 peak.
If Br is present,M+2 is equal to M+.
If Cl is present,M+2 is one-third of M+.
If iodine is present,peak at 127,large gap.
If N is present,M+ will be an odd number.
If S is present,M+2 will be 4% of M+,=>
Chapter 12 40
Isotopic Abundance
=>
81Br
Chapter 12 41
Mass Spectrum
with Sulfur
=>
Chapter 12 42
Mass Spectrum
with Chlorine
=>
Chapter 12 43
Mass Spectrum
with Bromine
=>
Chapter 12 44
Mass Spectra
of Alkanes
More stable carbocations will be more
abundant.
=>
Chapter 12 45
Mass Spectra
of Alkenes
Resonance-stabilized cations favored.
=>
Chapter 12 46
Mass Spectra
of Alcohols
Alcohols usually lose a water molecule.
M+ may not be visible.
=>
Chapter 12 47
End of Chapter 12