Solution 2.9.4.10 For F(s)= A s + B s +1 + C s ; 1 : A = sF(s)j s=0 = d ds  1 (s +1)(s; 1)  j s=0 = ;1 B = (s +1)F(s)j s=;1 =  1 s(s ; 1)  j s=;1 = 0:5: C = = (s ; 1)F(s)]j s=1 =  1 s(s +1)  j s=1 = 0:5: f(t)=[;1+0:5e ;t +0;;5e t ]1(t): 1