Solution 2.9.4.10
For
F(s)=
A
s
+
B
s +1
+
C
s ; 1
:
A = sF(s)j
s=0
=
d
ds
1
(s +1)(s; 1)
j
s=0
= ;1
B = (s +1)F(s)j
s=;1
=
1
s(s ; 1)
j
s=;1
= 0:5:
C = = (s ; 1)F(s)]j
s=1
=
1
s(s +1)
j
s=1
= 0:5:
f(t)=[;1+0:5e
;t
+0;;5e
t
]1(t):
1