Solution 3.8.1.9 Applying the Laplace transform, assuming zero initial conditions, yields s 3 Y (s)+10s 2 Y (s)+32sY (s)+32Y (s)=U(s);; or (s 3 +10s 2 +32s +32)Y (s)=U(s): Rearranging yields Y (s) U(s) = 1 s 3 +10s 2 +32s +32 : 1