Solution 3.8.1.2 Applying the Laplace transform, assuming zero initial conditions, yields s 3 Y (s)+4s 2 Y (s)+3sY (s)=U(s)+5sU(s);; or (s 3 +4s 2 +3s)Y (s)=U(s)(5s +1): Rearranging yields Y (s) U(s) = 5s +1 s 3 +4s 2 +3s : 1