Solution 3.8.1.10 Applying the Laplace transform, assuming zero initial conditions, yields s 3 Y (s)+10s 2 Y (s)+32sY (s)+32Y (s)=U(s)+6sU(s);; or (s 3 +10s 2 +32s +32)Y (s)=U(s)(6s +1): Rearranging yields Y (s) U(s) = 6s +1 s 3 +10s 2 +32s +32 : 1