Solution 3.8.1.12 Applying the Laplace transform, assuming zero initial conditions, yields s 3 Y (s)+12s 2 Y (s)+36sY (s)+32Y (s)=U(s)+2sU(s);; or (s 3 +12s 2 +36s)Y (s)=U(s)(2s +1): Rearranging yields Y (s) U(s) = 2s +1 s 3 +12s 2 +36s : 1