§ 2-1 Nodal analysis
We must apply KCL to nodes 1 and 2
??
?
???
??
22120
32070
21
21
??
??
..
..or
We select one node as a reference node,and then
define a voltage between each remaining node and the
reference node.
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?
?
?
???
?
?
?
?
?
)( 2
51
3
52
122
211
???
???
??
?
? V.
V
52
5
2
1
?
?
WP
A.i
A 1535
50
3
5
???
??
fRe
1? 2?
A3
A2?
2 1
5 1?
fRe
2?
A3
A2?
2 1
5?5i
31)(2)(3:2 23212 ????? ?????n o d e
25)(4)(25:3 13233 ????? ?????n o d e
11437 321 ???? ???or
3263 321 ???? ???or
251124 321 ???? ???or
By Cramer's rule and determinants,we have
1
191
191
1124
263
437
11225
263
4311
1 ??
??
??
??
?
?
???
??
32 32 ?? ?? a n d
Now let us increase the number of nodes by one.
38431 3121 ?????? )()(:n o d e ????
1?
2? 3?
A25?
A8?
A3?
S1
S5
S4
S3 S2
fRe
I1
- 8 A
R4
0,2 5
R2
1
3,0 0 0 V
2,0 0 0 V
I2
- 3 A R5
0,5
R1
0,3 3 3 3
1,0 0 0 V
R3
0,2
0V
0
I3
- 2 5 A
)( 52223 ?? ??
)()()( 42894732 321 ?????? ???
031)(3:2 212 ????? sin o d e ???
025)(45:3 133 ????? sin o d e ???
)1(11437 321 ???? ???or
)2(343 21 ???? sior ??
)3(2594 31 ???? sior ??
Equations (1),(4),(5) may be solved
54
42
189
110
947
437
1122
9428
4311
1,??
?
?
?
?
??
?
???
??
38431 3121 ?????? )()(:n o d e ????
56515 32,,??? ??
?? V22
si
1?
2? 3?
A25?
A8?
A3?
S1
S5
S4
S3
fRe
1,Make a neat,simple,circuit diagram,Indicate all
element and source values,Each source should have its
reference symbol.
2,Assuming that the circuit has N nodes,choose one
of these nodes as a reference node,Then write node
voltages v1,v2,… vN-1 at their respective nodes,
remembering that each node voltage is under-stood to
be measured with respect to the chosen reference.
Let us summarize the method by which we
obtain a set of nodal equations for any resistive
circuit:
3,If the circuit contains only current sources,apply
Kirchhoff 's current law at each non-reference node,To
obtain the conductance matrix if a circuit has only
independent current sources,equate the total current
leaving each node through all conductance to the total
source current entering that node,and order the terms
from v1 to vN-1,For each dependent current source
present,relate the source current and the controlling
quantity to the variables v1,v2,…,v N -1,if they are not
already in that form.
4.If the circuit contains voltage sources,temporarily
modify the given circuit by replacing each such source
by a short circuit,thus reducing the number of nodes
by one for each voltage source that is present,The
assigned node voltages should not be changed,
Using these assigned node-to-reference voltage,apply
Kirchhoff 's current law at each of the nodes or super-
nodes in this modified circuit,Relate each source
voltage to the variables v1,v2,…,v N-1,if it is not already
in that form.
Example 2,
(A) If X=2S.Find the power supplied by the 10A source;
(B) If X=10V,Find the power supplied by the 10A source;
(C) If X=v1/3,Find v1 ;
(D)If X= 4v1/3,Find v1.
Solution:
3/251 ?v
WvP A 3.8310110 ???
?
?
?
?
?
????
????
???
2063
0392
1023
321
321
321
vvv
vvv
vvv
)(A
4.14,10 13 ?? vVv
WP A 14410 ?
)(B
3.4,3/ 113 ?? vvv)(C
X 2
Vvvvvvv 8.23,3/420)(3)(1 112313 ??????)(D
? V10
??
? 3/
1v
3/4 1v
DP,use nodal analysis to find if elementX?
)(VX)C(
X)B(
AX)A(
???
??
?
10
8
2
VA 42)( ? VB 24)( ?
VC 6.19)( ??
1?
A9
A17
6 4 2
2?
?
?
x?
.fRe
X
A28V10? ?
321,,::2 vvvF i n dDP ?
532 ?? ??
2,3,1 321 ???? ???
(与电流源串联的电阻不介入节点方程 )
Find:P2V,
Find,P2A.
WPAi V 21 21 ??
00 22 ?? AA P?
2111 31211 ????? ?????
2111 13212 ????? ?????
?
?
V2
A2
1
1
1
1
1
1i
?
?
A2?
?? V51?
2? 3?
fRe
We must apply KCL to nodes 1 and 2
??
?
???
??
22120
32070
21
21
??
??
..
..or
We select one node as a reference node,and then
define a voltage between each remaining node and the
reference node.
?
?
?
?
?
???
?
?
?
?
?
)( 2
51
3
52
122
211
???
???
??
?
? V.
V
52
5
2
1
?
?
WP
A.i
A 1535
50
3
5
???
??
fRe
1? 2?
A3
A2?
2 1
5 1?
fRe
2?
A3
A2?
2 1
5?5i
31)(2)(3:2 23212 ????? ?????n o d e
25)(4)(25:3 13233 ????? ?????n o d e
11437 321 ???? ???or
3263 321 ???? ???or
251124 321 ???? ???or
By Cramer's rule and determinants,we have
1
191
191
1124
263
437
11225
263
4311
1 ??
??
??
??
?
?
???
??
32 32 ?? ?? a n d
Now let us increase the number of nodes by one.
38431 3121 ?????? )()(:n o d e ????
1?
2? 3?
A25?
A8?
A3?
S1
S5
S4
S3 S2
fRe
I1
- 8 A
R4
0,2 5
R2
1
3,0 0 0 V
2,0 0 0 V
I2
- 3 A R5
0,5
R1
0,3 3 3 3
1,0 0 0 V
R3
0,2
0V
0
I3
- 2 5 A
)( 52223 ?? ??
)()()( 42894732 321 ?????? ???
031)(3:2 212 ????? sin o d e ???
025)(45:3 133 ????? sin o d e ???
)1(11437 321 ???? ???or
)2(343 21 ???? sior ??
)3(2594 31 ???? sior ??
Equations (1),(4),(5) may be solved
54
42
189
110
947
437
1122
9428
4311
1,??
?
?
?
?
??
?
???
??
38431 3121 ?????? )()(:n o d e ????
56515 32,,??? ??
?? V22
si
1?
2? 3?
A25?
A8?
A3?
S1
S5
S4
S3
fRe
1,Make a neat,simple,circuit diagram,Indicate all
element and source values,Each source should have its
reference symbol.
2,Assuming that the circuit has N nodes,choose one
of these nodes as a reference node,Then write node
voltages v1,v2,… vN-1 at their respective nodes,
remembering that each node voltage is under-stood to
be measured with respect to the chosen reference.
Let us summarize the method by which we
obtain a set of nodal equations for any resistive
circuit:
3,If the circuit contains only current sources,apply
Kirchhoff 's current law at each non-reference node,To
obtain the conductance matrix if a circuit has only
independent current sources,equate the total current
leaving each node through all conductance to the total
source current entering that node,and order the terms
from v1 to vN-1,For each dependent current source
present,relate the source current and the controlling
quantity to the variables v1,v2,…,v N -1,if they are not
already in that form.
4.If the circuit contains voltage sources,temporarily
modify the given circuit by replacing each such source
by a short circuit,thus reducing the number of nodes
by one for each voltage source that is present,The
assigned node voltages should not be changed,
Using these assigned node-to-reference voltage,apply
Kirchhoff 's current law at each of the nodes or super-
nodes in this modified circuit,Relate each source
voltage to the variables v1,v2,…,v N-1,if it is not already
in that form.
Example 2,
(A) If X=2S.Find the power supplied by the 10A source;
(B) If X=10V,Find the power supplied by the 10A source;
(C) If X=v1/3,Find v1 ;
(D)If X= 4v1/3,Find v1.
Solution:
3/251 ?v
WvP A 3.8310110 ???
?
?
?
?
?
????
????
???
2063
0392
1023
321
321
321
vvv
vvv
vvv
)(A
4.14,10 13 ?? vVv
WP A 14410 ?
)(B
3.4,3/ 113 ?? vvv)(C
X 2
Vvvvvvv 8.23,3/420)(3)(1 112313 ??????)(D
? V10
??
? 3/
1v
3/4 1v
DP,use nodal analysis to find if elementX?
)(VX)C(
X)B(
AX)A(
???
??
?
10
8
2
VA 42)( ? VB 24)( ?
VC 6.19)( ??
1?
A9
A17
6 4 2
2?
?
?
x?
.fRe
X
A28V10? ?
321,,::2 vvvF i n dDP ?
532 ?? ??
2,3,1 321 ???? ???
(与电流源串联的电阻不介入节点方程 )
Find:P2V,
Find,P2A.
WPAi V 21 21 ??
00 22 ?? AA P?
2111 31211 ????? ?????
2111 13212 ????? ?????
?
?
V2
A2
1
1
1
1
1
1i
?
?
A2?
?? V51?
2? 3?
fRe