Signals and Systems
Fall 2003
Lecture #20
20 November 2003
1,Feedback Systems
2,Applications of Feedback Systems
Why use Feedback?
Reducing Effects of Nonidealities
Reducing Sensitivity to Uncertainties and Variability
Stabilizing Unstable Systems
Reducing Effects of Disturbances
Tracking
Shaping System Response Characteristics (bandwidth/speed)
A Typical Feedback System
One Motivating Example
Open-Loop System Closed-Loop Feedback System
Analysis of (Causal!) LTI Feedback Systems,Black’s Formula
CT System
Black’s formula (1920’s)
Closed - loop system function =
forward gain
1 - loop gain
Forward gain — total gain along the forward path from the input to the output
Loop gain — total gain around the closed loop
Applications of Black’s Formula
Example:
1)
2)
The Use of Feedback to Compensate for Nonidealities
Assume KP(jω) is very large over the frequency range of interest,
In fact,assume
— Independent of P(s)!!
Example of Reduced Sensitivity
10
)0990)(1000(1
1000
)(
0990)(1000)(
1
11
=
+
=
==
.
jQ
.jG,jKP
ω
ωω
1)The use of operational amplifiers
2)Decreasing amplifier gain sensitivity
Example:
(a) Suppose
(b) Suppose
(50% gain change)
99
)0990)(500(1
500
)(
0990)(500)(
2
22
.
.
jQ
.jG,jKP
+
=
==
ω
ωω
(1% gain change)
Fine,but why doesn’t G(jω) fluctuate?
Note:
Needs a large loop gain to produce a steady (and linear) gain for the
whole system.
Consequence of the negative (degenerative) feedback.
For amplification,G(jω) must attenuate,and it is much easier to
build attenuators (e.g,resistors) with desired characteristics
There is a price:
Example,Operational Amplifiers
If the amplitude of the loop gain
|KG(s)| >> 1 — usually the case,unless the battery is totally dead.
The closed-loop gain only depends on the passive components
(R
1
& R
2
),independent of the gain of the open-loop amplifier K.
Then
Steady State
The Same Idea Works for the Compensation for Nonlinearities
Example and Demo:
Amplifier with a Deadzone
The second system in the forward path has a nonlinear input-output
relation (a deadzone for small input),which will cause distortion if it is
used as an amplifier,However,as long as the amplitude of the,loop gain”
is large enough,the input-output response? 1/K
2
Improving the Dynamics of Systems
Example,Operational Amplifier 741
The open-loop gain has a very large value at dc but very limited bandwidth
Not very useful on its own
Stabilization of Unstable Systems
P(s) — unstable
Design C(s),G(s) so that the closed-loop system
is stable
poles of Q(s) = roots of 1+C(s)P(s)G(s) in LHP
Example #1,First-order unstable systems
Example #2,Second-order unstable systems
— Unstable for all values of K
— Physically,need damping — a term proportional to s? d/dt
Example #2 (continued):
Attempt #2,Try Proportional-Plus-Derivative (PD) Feedback
— Stable as long as K
2
> 0 (sufficient damping)
and K
1
> 4 (sufficient gain).
Example #2 (one more time):
Why didn’t we stabilize by canceling the unstable poles?
There are at least two reasons why this is a really bad idea:
a) In real physical systems,we can never know the precise
values of the poles,it could be 2±?.
b) Disturbance between the two systems will cause instability.
Demo,Magnetic Levitation
i
o
= current needed to balance the weight W at the rest height y
o
Force balance
Linearize about equilibrium with specific values for parameters
— Second-order unstable system
Magnetic Levitation (Continued):
—Stable!
Fall 2003
Lecture #20
20 November 2003
1,Feedback Systems
2,Applications of Feedback Systems
Why use Feedback?
Reducing Effects of Nonidealities
Reducing Sensitivity to Uncertainties and Variability
Stabilizing Unstable Systems
Reducing Effects of Disturbances
Tracking
Shaping System Response Characteristics (bandwidth/speed)
A Typical Feedback System
One Motivating Example
Open-Loop System Closed-Loop Feedback System
Analysis of (Causal!) LTI Feedback Systems,Black’s Formula
CT System
Black’s formula (1920’s)
Closed - loop system function =
forward gain
1 - loop gain
Forward gain — total gain along the forward path from the input to the output
Loop gain — total gain around the closed loop
Applications of Black’s Formula
Example:
1)
2)
The Use of Feedback to Compensate for Nonidealities
Assume KP(jω) is very large over the frequency range of interest,
In fact,assume
— Independent of P(s)!!
Example of Reduced Sensitivity
10
)0990)(1000(1
1000
)(
0990)(1000)(
1
11
=
+
=
==
.
jQ
.jG,jKP
ω
ωω
1)The use of operational amplifiers
2)Decreasing amplifier gain sensitivity
Example:
(a) Suppose
(b) Suppose
(50% gain change)
99
)0990)(500(1
500
)(
0990)(500)(
2
22
.
.
jQ
.jG,jKP
+
=
==
ω
ωω
(1% gain change)
Fine,but why doesn’t G(jω) fluctuate?
Note:
Needs a large loop gain to produce a steady (and linear) gain for the
whole system.
Consequence of the negative (degenerative) feedback.
For amplification,G(jω) must attenuate,and it is much easier to
build attenuators (e.g,resistors) with desired characteristics
There is a price:
Example,Operational Amplifiers
If the amplitude of the loop gain
|KG(s)| >> 1 — usually the case,unless the battery is totally dead.
The closed-loop gain only depends on the passive components
(R
1
& R
2
),independent of the gain of the open-loop amplifier K.
Then
Steady State
The Same Idea Works for the Compensation for Nonlinearities
Example and Demo:
Amplifier with a Deadzone
The second system in the forward path has a nonlinear input-output
relation (a deadzone for small input),which will cause distortion if it is
used as an amplifier,However,as long as the amplitude of the,loop gain”
is large enough,the input-output response? 1/K
2
Improving the Dynamics of Systems
Example,Operational Amplifier 741
The open-loop gain has a very large value at dc but very limited bandwidth
Not very useful on its own
Stabilization of Unstable Systems
P(s) — unstable
Design C(s),G(s) so that the closed-loop system
is stable
poles of Q(s) = roots of 1+C(s)P(s)G(s) in LHP
Example #1,First-order unstable systems
Example #2,Second-order unstable systems
— Unstable for all values of K
— Physically,need damping — a term proportional to s? d/dt
Example #2 (continued):
Attempt #2,Try Proportional-Plus-Derivative (PD) Feedback
— Stable as long as K
2
> 0 (sufficient damping)
and K
1
> 4 (sufficient gain).
Example #2 (one more time):
Why didn’t we stabilize by canceling the unstable poles?
There are at least two reasons why this is a really bad idea:
a) In real physical systems,we can never know the precise
values of the poles,it could be 2±?.
b) Disturbance between the two systems will cause instability.
Demo,Magnetic Levitation
i
o
= current needed to balance the weight W at the rest height y
o
Force balance
Linearize about equilibrium with specific values for parameters
— Second-order unstable system
Magnetic Levitation (Continued):
—Stable!