§ 14-7 Applications in circuit analysis
We consider each term of the Fourier aeries
representing the voltage as a single source.
The equivalent impedance of the network at is
used to compute the current at that harmonic.
?n
CnXa n dLnX nCnL ?? /1)()( ???
The sum of these individual responses is the total
response i.
Solution,At,Z(0)=5 I(0)=100/5=20A00 ??
At =500 1/s Z(1)=5+j500(20)10-3=5+j10?
AZVI ??????
??
??
?
?
4.63
2
48.4
4.6325.11
0
2
50
)1(
)1(
)1( Ati )4.63s in (48.4)1( ??? ?
?At 3 =1500 1/s Z(3)=5+j1500(20)10-3=5+j30
AZVI ??????
??
??
?
?
5.80
2
8 2 3.0
5.804.30
0
2
25
)3(
)3(
)3( Ati )5.803s i n (823.0)3( ??? ?
Atti )5.803s i n (8 2 3.0)4.63s i n (48.420 ??????? ??
..20,5,/1500
,3s i n25s i n50100
:
iF i n dmHLRs
tVtIf
E x a m p l e
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?
???
WIVIVIVP 2053co sco s 3)3()3(1)1()1()0()0( ???? ??
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