1
1
bvDè0y?" ù?
5 [
5 [
Baè
^ ("d )¥o?
>?#?
S?
1,
>?¥? ?eyD+?
? ?á
3 e y+ ?! ?
dL?
> ?
q VA +?¥
dL?
{á
3?
¥
qs

zdL?
zo??K
L?
>?
(
q
> ? )
z
{? z
?
>?
zM
+?d°L
Mê
>?
{?á
3
?¥
qs

z
{?|
zL?è F
qT¨
5 [
2
bvDè0y?" ù?
2,
>?D??
>?¥
ZE
(1)μLE¨ ACμL (5 2.2.2,2.2.6)
(2)°
@.
{+?E NPN5 CEbvè
^
V
CC
?
?
u


u
b
v
u
ν
I0
Q
V
om1
V
om2
ν
O
??yT u×
?
S?
Q?
êú
Q?
ê?
KD Q?
a¨ DCò
??yT u×
?
S?
?
êú
?
ê?
KD ?
a¨ ò
5 [
2
3
bvDè0y?" ù?
(3))bvè
^¥?
S?s
)B??¨m3Eb
"s
{)[?A?s -
ò) f ?b
??yT? Q?aQ_Kv?? |l?b
D
{è
@# RLμ1, %?
^?
r?Kv (DK
?¨ )b
?
"?X??]'éM]b
)B??¨m3Eb
"s
{)[?A?s -
ò) f ?b
??yT? ?aQ_Kv?? |l?b
D
{è
@# Lμ1, %?
^?
r?Kv (DK
?¨ )b
?
"?X??]'éM]b
5 2.8.4a2.9.1a2.9.2a*2.9.3
5 [
4
bvDè0y?" ù?
5 2.2.2
m3E
V
O
T
R
3
V
CC
+
_
R
S

@Y
^
V
BB
V
O
T
v
S
R
3
V
CC
+
_
+
_
R
S
5m 2.2.2
V
BB
5 [
uAmA
R
VV
I
B
BEQBB
BQ
48048.0
2.6
7.01
==
=
=
I
BQ
| 40uA
50uA
I
BQ
| 40uA
50uA
Tm ——
{ ?μL
v
BE
i
B
0
V
BEQ
40uA
Q
1V0.5V
80uA
3
5
bvDè0y?" ù?
5 2.2.2(m3E
V
O
T
R
3
V
CC
+
_
R
S

@Y
^
V
BB
5 [
6
2
+?=+?=
=
CE
C
CC
C
CE
C
CECC
CQ
V
R
V
R
V
R
VV
I
Tm ——
{μL
D 40uA
50uA+? wL??1 Q
4V 4mA
v
BE
i
B
0
V
BEQ
40uA
Q
1V0.5V
80uA
v
CE
i
C
0 4V
2mA
Q
12V
20uA
40uA
60uA
4mA
6mA
?
S? min(4 V
CES
 12 4)" 3.6V
?
S? min(4 V
CES
 12 4)" 3.6V
6
bvDè0y?" ù?
5 2.2.2(m3E
V
O
T
R
3
V
CC
+
_
R
S

@Y
^
V
BB
5 [
v
BE
i
B
0
40uA
Q
1V0.5V
80uA
v
CE
i
C
0 4V
2mA
Q
12V
20uA
40uA
60uA
4mA
6mA
wtmVv
s
sin100=
i
B
i
C
v
O
4
7
bvDè0y?" ù?
5 2.2.6
? |
ê?è
^?
r?èa÷
V
O
T
R
1
v
S
R
3
R
L
V
CC
C
1
C
2
+
_
+
_
R
2
R
S
R
4
5m 2.2.6
+
_
V
i
5 [
?≈==
+
= k3.17//,V2
21BCC
21
2
BB
RRRV
RR
R
V
()
() b

V6.863.162.03.315
,mA63.1A3.16
1
CEQ
CQ
4B
BEBB
BQ
≈×+?≈
≈≈
++
=
V
I
RR
VV
I μ
β
8
bvDè0y?" ù?
5 2.2.6
? |
ê?è
^?
r?èa÷
?-
{ RE¥Hq
? ?
S?
V
O
T
R
1
v
S
R
3
R
L
V
CC
C
1
C
2
+
_
+
_
R
2
R
S
R
4
5m 2.2.6
+
_
V
i
0
V
CE(sat)
V
CEQ
v
CE
Q
M
N
I
CQ
i
c
V
om1
V
om2
VpRIV
LCQom
6.3
'
2
≈=
5 [
?? V
CEQ
?v?
S?? V
om2
%?
?? V
CEQ
?v?
S?? V
om2
%?
5
9
bvDè0y?" ù?
v
O
R
6
R
1
R
5
V
CC
5m 2.8.4
R
2
R
3
+
v
i
_
D
V
BB
T
1
T
2
T
3
R
4
5 [
b5?
S?1
¥μ_?
S?1
¥?_?
S?1
á

)67.3(V34.7
,V67.323.39.6;V1.5
V9.63
pp
2B2Co
C2QCCo
5C2CCC2Q
p
Q
V
VV
VV
RIVV
?=
=
==
ν
ν
10
bvDè0y?" ù?
5 2.2.5
2
v
O
T
R
1
R
2
v
S
R
3
R
L
V
CC
C
1
C
2
C
3
+
_
+
_
R
S
()
A8.30
1
321
BECC
BQ
μ
β

+++
=
RRR
VV
I
 mA08.3
CQ
≈I
,
V84.3
CQ33CCCEQ
=?= IRVV
v
O
T
R
1
R
R
3
v
i
?
@Y
^
i
b
i
c
+
_
+
_
R
L
R
S
v
s
+
_
2
b

124
k18.1////
be
L
L32L
=

=
≈=′
r
R
A
RRRR
ν
β
&
b

≈≈
≈=
k2//
k91.0//
32o
be1
RRR
rRR
i
b102
S
S

+
=
νν
A
RR
R
A
i
i
&&
5 [
6
11
bvDè0y?" ù?
5 [
5 [
Kv
{?
μ_ Vμ" V
CC
-|V
BE5
|-V
CES1
=13.8V
?_N
H T
1
¤í??
5m 2.9.1
V
?
" V
CC
–i
B4max
R
C
– v
BE4
± I5 ?T T
1
^è
@÷μ
v
Omax
≈$ (5 2.9.2
4úKv
{?¥÷E —1 è
^

5m 2.9.3
Kv
{?
μ_ Vμ" V
CC
-|V
BE5
|-V
CES1
=13.8V
?_N
H T
1
¤í??
5m 2.9.1
V
?
" V
CC
–i
B4max
R
C
– v
BE4
± I5 ?T T
1
^è
@÷μ
v
Omax
≈$ (5 2.9.2
4úKv
{?¥÷E 1 è
^

5m 2.9.3
( )
LC
4L
LC
BE4CC
b4max
Lb4max
)1(
)1
,
1
,1
RR
VVR
V
RR
VV
I
RIV
BECC
++
=
+
=
+=
β
β
β
β




?
?
v
O
5m 2.9.1
+
R
C
v
I
R
L
-V
CC
V
CC
T
4
T
5
i
o
T
1
T
3
T
2
12
bvDè0y?" ù?
v
O
5m 2.9.2
+
D
1
v
I
R
L
-V
CC
V
CC
T
4
T
5
i
o
T
1
T
3
T
2
D
2
I
R
5 [
()
í1D
 (1
{èa¥?μ_?
LBEsatCECC
,V1.14
1
RVVV ≈
7
13
bvDè0y?" ù?
5 2.9.3
(1) v
o
{?_?
sK?ù5
?_?Kv
{?
v
Kmax
≈V
CC
– i
B2max
R
C
– v
BE2
V
om
≈ V
CC
/2- i
B2max
R
C
– v
BE2
3 %÷E
c ?) T
1
??è
d1 
R
L
+V
CC
T
2
v
o
T
1
R
1
R
2
T
3
C
1
C
2
v
i
C
3
R
3
A
K
R
4
(2) 1 e ?T¨
C
3

èa V
C3
=V
CC
/2 -V
R4
≈V
CC
/2
z
HWè
R
4
C
3
>>T(?|?
ù )
C
3
M??èya÷ V
C3
z1 T¨
v
A
= v
o
+ V
C3
V[v? V
CC
 T
2
V[r
V
om
= V
CC
/2-V
CE(sat)
(2) 1 e ?T¨
C
3

èa V
C3
=V
CC
/2 -V
R4
≈V
CC
/2
z
HWè
R
4
C
3
>>T(?|?
ù )
C
3
M??èya÷ V
C3
z1 T¨
v
A
= v
o
+ V
C3
V[v? V
CC
 T
2
V[r
V
om
= V
CC
/2-V
CE(sat)
5 [
14
bvDè0y?" ù?
=aμbè
^s
5 2.7.2a2.7.4
T
4
T
1 T
2
R
E3
-V
EE
v
o
+
_
v
ID
V
CC
5 2.7.2
T
3
R
C2
R
C1
R
2
R
1
5 [
13 bebe
rr ≠
()
V1.107.07.015.012
V95.0612:
2
BE1BE3EQ3E3EE
CQ1C1CCICM
EBOBRBEIDM
=++×+?=+++?
=×?=?
+≈
VVIRV
IRVV
VVV
μ_1
 ?_1
 
++
+=
E3be3B
E3
ceo3
1
RrR
R
rR
β

@÷
{èE
8
15
bvDè0y?" ù?
T
1
T
2
R
3
R
4
V
CC
-V
EE
v
o
v
I1
v
I2
T
4
T
3
R
6
R
5
R
2
R
1
R
9
R
8
R
7
R
11
R
10
D
5m 2.8.2
5 [
++
+≈
7be498
7
ce4o4
//
1
RrRR
R
rR
β
16
bvDè0y?" ù?
?a
Y+?s
1,?Yè
^# 
Y

+?
2,úYè
^# 
Y
?
+?
3,bvè
^¥
Y+??
4,
a/K??
q¥s
5,??
,?à
Q
5 [
V
S

R
S

V
b’e
C
i
b£
C
b’c
e




g
m
V
b’e
r
ce

Vo

c
R
L

V
S
C
1

C
2

,
2
1
'
1
1
RC
f
L
π
=
'
2
2
2
1
RC
f
L
π
=
2
2
2
1 LLL
fff +=
''
2
1
iS
H
CR
f
π
=
9
17
bvDè0y?" ù?
5 2.3.5a2.3.6
i
b
v
b’e
R
B
r
b’e
Cb’e
r
bb’
££
b
e


m
g
v
b’e

v
o

i
c
c
v
S
R
S
R’
L
C
M
C’
M
C
i
R
S

v
O
T
R
B
v
S
R
C
R
L
V
CC
5m 2.3.5
C
1
C
2
+
_
+
_
R
s
( )
[]()
SSBbbebS
cb
T
m
cb
Teb
eb
LCL
bcLmebMeb
//201.0//1////
pF8.37
22
1
k2//
1
RRRrrR
C
f
g
C
fr
C
RRR
CRgCCCC
i
+=+=′
=?≈?
+
=
==′
′′++=+=
′′
′′


′′



ππ
β
5 [
18
bvDè0y?" ù?
v
O
T
R
B
v
S
R
C
R
L
V
CC
5m 2.3.5
C
1
C
2
+
_
+
_
R
s
V
S
C
1
C
2

R
S
r
bb’
R
B r
b’e
R
C
R
L
()()
()
Hz0.9
22
1
2.204.12
1
//2
1
2LC
L2
S1beBS
L1
=
+
=
×+
=
+
=
CRR
f
RCrRR
f 
ππ
5 2.3.5a2.3.6
5 [
10
19
bvDè0y?" ù?
1aè
@÷

@÷¥
{èE
5 2.6.3 (
{
5 2.6.4
R’T¨1 T’?
4è
@Y
^
 £&V74ú?^ú
T
1
T
2
I
R
R
r
I
O
V
CC
R
E1
R
E2
())rR//(RR
RRr
R
1rR
D1ErB
2EBbe
2E
2ceO
+=
++
+≈
β
5 [
20
bvDè0y?" ù?
G
i
v
gsm
vg
r
ds
S
o
v
D
R
D
bsmb
vg
v
I
R
D
V
DD
v
O
V
G
M
i
i
Ddsoiimbmo
Rrvvvggv ]/)()[(?++=
dsD
Ddsmbm
v
rR
Rrgg
A
/1
)/1(
+
++
=
H?
Dds
Rr >>
Dmbmv
RggA )( +≈
ivo
dsoimbmii
vAv
rvvggvi
=
++= /)()(
{
dsmbm
D
mbmdsmbm
Dds
i
i
i
rgg
R
ggrgg
Rr
i
v
R
)(
1
)(1 +
+
+

++
+
==
dsDo
rRR //=
? ?c -3.2 MOSIC¥?)bvè
^
3.
E
CG
3.2.2 MOS5 ??F
'bvè
^
?
11
21
bvDè0y?" ù?
3.2.3 MOSμ÷μ
1,9 <? MOS5 (E)μ÷èE
v
DS
Q
i
D
0
v
GS
= v
DSv
GS
= v
DS
g
mb
V
bs
r
ds
g
m
V
gs
V
ds
V
gs
+
+
-
-
G B D
?rèE
m
ds
mbm
g
1
r//
g
1
//
g
1
r ≈=
2,{D? MOS5 (D)μ÷èE
v
DS
Q
i
D
0
v
GS
=0
G S
g
mb
V
bs
V
ds
+
-
B D
r
ds
ds
mb
r//
g
1
r=
i
D
r
V
DD
i
D
r
V
DD
? ?c -3.2 MOSIC¥?)bvè
^
22
bvDè0y?" ù?
3.2.4 'bv?íè
^
1,E/Dbvè
^
T
2
T
1
v
1
v
0
7
%%
g
m1
V
gs1
V
ds
+
-
+
-
V
i
=V
gs1
r
r
ds1

@yT?
!?
?
@?
l?|?rè
^
R
o
= r
ds1
//r = r
ds1
//r
ds2
// (1/ g
mb2
)
R
L
′= r
ds1
//r = r
ds1
//r
ds2
// (1/ g
mb2
)
=
=
2mb
2ds1ds1m
'
L1mV
g
1
//r//rg
RgA
? ?c -3.2-3.2.4 'bv?íè
^
12
23
bvDè0y?" ù?
2,E/Ebvè
^
T
2
T
1
v
1
v
0
7
%%
g
m1
V
gs1
V
ds
+
-
+
-
V
i
=V
gs1
r
r
ds1
R
o
= r
ds1
//r
=
=
2mb2m
2ds1ds1m
'
L1mV
g
1
//
g
1
//r//rg
RgA
2mb2m
2ds
g
1
//
g
1
//rr =
2mb2m
2ds1ds1ds
'
L
g
1
//
g
1
//r//rr//rR ==
? ?c -3.2 -3.2.4 'bv?íè
^
24
bvDè0y?" ù?
3 CMOSbvè
^
T
2
T
1
v
1
v
0
7
%%
7
(

^F?
50yT
Hq

I
>V
GS(th)1
 ν
O
≥ν
I
-V
GS(th)1

GS2
= V
G
-V
DD
< V
GS(th)2
V
BS
=0 íE (é??? )r?
g
m1
V
gs1
V
ds
+
-
+
-
V
i
=V
gs1
r
ds2
r
ds1
1,l?|+?
A
V
= - g
m
(r
ds1
//r
ds2
)
R
o
= r
ds1
//r
ds2
? ?c -3.2 -3.2.4 'bv?íè
^