Solution 3.8.3.4 Let Z 1 = R 1 k C 1 = R 1 C 1 s R 1 + 1 C 1 s = R 1 R 1 C 1 s +1 ;; and Z 2 = 1 C 2 s : Then Z 2 Z 1 = 1 C 2 s R 1 R 1 C 1 s +1   (R 1 C 1 s +1)(C 2 s) (R 1 C 1 s +1)(C 2 s)  = (R 1 C 1 s +1) R 1 C 2 = (C 1 =overC 2 )[s+(1=R 1 C 1 )] s : We next havetochoose some values. We knowthat C 1 C 2 = 10 1 R 1 C 1 = 5 Let R 1 = 200 k C 1 = 1:0  f C 2 = 0:1  f: 1