Solution 3.8.5.1 For the opamp circuit of Figure 3.26 wehave V o (s) V i (s) = ;(1=R 1 C 1 )s s 2 +(1=R 2 C 1 +1=R 2 C 2 )s +1=R 1 C 1 R 2 C 2 Wewishtomake the denominator (s +10)(s+100) Letting R 2 = aR 1 ;; C 2 = bC 1 ;; and =1=R 1 C 1 ;; weobtain V o (s) V i (s) = ; s s 2 + (1=a +1=ab)s+ 2 =ab : Then wehavethetwo equations [(b+1)=ab] = 110 2 =ab = 1000 Dividing the rst equation bythesecond yields b +1 =0:11;; or b =0:11 ;1 If we let =10then b =0:1;; and a = 2 b1000 = 100 0:11000 = 1: Then wemust have 1 R 1 C 1 = =10;; or R 1 C 1 =0:1 1 Wechoose R 1 =100k and C 1 =1 f: Then R 2 = R 1 100 k and C 2 =0:1  f 2