solution 9.10.1.14 The rst step is to put the transfer function in time constant form. So we have G(s) = 101 s(s 2 +2s +101) = 101 26s(s= p 101) 2 +(2=101)s+1) = 1 s(s= p 101) 2 +(2=101)s+1) : Then the terms to be plotted are 1 ;; 1 s ;;and 1 s= p 101) 2 +(2=101)s+1 : 20log 10 (1) = 0 dB Atlowfrequencies the only terms that contribute are the gain and 1=s. The term 1=s, whichisastraightline crossing the 0-dB line at ! =1,withslope ;20 dB/dec. When the gain is added in, it will still cross ! =1rad/s at 0 dB, since the gain, in dB, is zero. The quadratic term is a straight line out to the vicinityofthe natural frequency ! n ,and a straightline for frequencies much larger than ! n . The twostraightline asymptotes shown in Figure 1 capture the behavior awayfromthe vicinityof! n .Notethat the slope changes to ;60 dB when the plot crosses the 0-dB line. The damping ratio of the complex poles is about 0.095. Referring to Figure 9.11(a) wesee that there will be signi canthump at the resonantfrequency ( whichisvery close to ! n ). Weestimate the heightofthe hump from the damping ratio to be about 15 dB. The accurate magnitude plot, also shown in Figure ??, was generated with the MATLAB statements w=logspace(-2,3,200);; w=logspace(-2,3,200);; s=j*w;; p1 = 0 p2 = 1 -j*10 p3 = 1 + j*10 K=101 mag = 20.*log10( K ./( abs( s + p1) .* abs(s + p2).*abs(s + p3) ) );; semilogx(w,mag);; grid on axis([0.1 100 -80 40]) print -deps 910114a.ep 1 10 -1 10 0 10 1 10 2 -80 -60 -40 -20 0 20 40 Figure 1: Accurate and asymptotic Bode magnitude plots The phase plot, shown in Figure 2, is generated with the MATLAB statements w1 = logspace(-2,3,20);; s1 = j*w1;; phase = (- angle(s + p1)-angle(s + p2) - angle(s + p3) )*180/pi;; phase1 =( - angle(s1 + p1)-angle(s1 + p2) - angle(s1 + p3))*180/pi;; semilogx(w,phase,'k-',w1,phase1,'rd');; grid on axis([0.1 1000 -270 -90]) print -deps 910114b.eps zeta = cos(atan(10/1)) Note that twentypoint spread over vedecades will giveafairly accurate phase plot. The complete MATLAB program to drawbothplots is w=logspace(-2,3,200);; s=j*w;; p1 = 0 p2 = 1 -j*10 p3 = 1 + j*10 2 10 -1 10 0 10 1 10 2 10 3 -260 -240 -220 -200 -180 -160 -140 -120 -100 Figure 2: Accurate and approximate Bode phase plots K=101 mag = 20.*log10( K ./( abs( s + p1) .* abs(s + p2).*abs(s + p3) ) );; semilogx(w,mag);; grid on axis([0.1 100 -80 40]) print -deps 910114a.eps pause w1 = logspace(-2,3,20);; s1 = j*w1;; phase = (- angle(s + p1)-angle(s + p2) - angle(s + p3) )*180/pi;; phase1 =( - angle(s1 + p1)-angle(s1 + p2) - angle(s1 + p3))*180/pi;; semilogx(w,phase,'k-',w1,phase1,'rd');; grid on axis([0.1 1000 -270 -90]) print -deps 910114b.eps zeta = cos(atan(10/1)) 3