vDt ?
¨ i?
?
0-1X? m412 jia
vv
v
+= m10ib
vv
?=
ksY¨TmE?3Ep3
1 ba
v
v
+
2 ba
v
v
? b
3 (1) m)42(m)10412( jiijiba
vvvvv
v
v
+=?+=+
θ
j
v
4
ba
v
v
+
2042
22
=+=+ba
v
v
°== 4.63
2
4
arctanθ
(2) m)422(m)10412( jiijiba
vvvvvv
v
+=++=?
510422
22
=+=?ba
v
v
°== 3.10
22
4
arctanθ (m
{ ) i
v
2
0-2
O
jia
vv
v
126 += m68 jib
vv
v
??=
kp
1 ba
v
v
?
2 ba
v
v
× b
3 (1) 1207248)68()126( ?=??=???+=? jijiba
vvvv
v
v
(2) kkkjijiba
vvvvvvvv
v
609636)68()126( =+?=??×+=×
0-3?
O
?B?????m 0-3
?
U bX? m3|| =a
v
m4|| =b
v
m5|| =c
v
p
1 || ba
v
v
+
2 ba
v
v
?
3 ba
v
v
× b
3 (1) m5==?=+ ccba
vv
v
v
(2) ba
v
v
Q ⊥ 0=?∴ ba
v
v
(3) kijba
vvvv
v
1243 ?=×=×
0-4X? ktjeittr
t
vvv
v
5sin23)2(
23
+?+=
?
p/
ò
T 0=t
H¥′
1
t
r
d
d
v
2
t
r
d
d
v
3
t
r
r
d
d
v
v
?
4
t
r
r
d
d
v
v
× b
3 (1) ktjeit
t
r
t
vvv
v
5cos106)23(
d
d
22
+++=
?
0=t
H jr
v
v
3= kji
t
r
vvv
v
1062
d
d
++=
(2) 1401062
d
d
222
=++=
t
r
v
(3) 18)106()3(
d
d
?=+??=? kjj
t
r
r
vvv
v
v
(4) ikjj
t
r
r
vvvv
v
v
30)106()3(
d
d
?=+×?=×
1