vDt ? ¨ i? ? 0-1X? m412 jia vv v +=  m10ib vv ?=  ksY¨TmE?3E p3  1 ba v v +   2 ba v v ? b 3 (1) m)42(m)10412( jiijiba vvvvv v v +=?+=+ θ j v 4 ba v v + 2042 22 =+=+ba v v °== 4.63 2 4 arctanθ (2) m)422(m)10412( jiijiba vvvvvv v +=++=? 510422 22 =+=?ba v v °== 3.10 22 4 arctanθ (m { ) i v 2 0-2  O  jia vv v 126 +=  m68 jib vv v ??=  k p  1 ba v v ?   2 ba v v × b 3 (1) 1207248)68()126( ?=??=???+=? jijiba vvvv v v (2) kkkjijiba vvvvvvvv v 609636)68()126( =+?=??×+=× 0-3 ? O ?B? ??? ?m 0-3 ? UbX? m3|| =a v  m4|| =b v  m5|| =c v  p  1 || ba v v +   2 ba v v ?   3 ba v v × b 3 (1) m5==?=+ ccba vv v v (2) ba v v Q ⊥  0=?∴ ba v v (3) kijba vvvv v 1243 ?=×=× 0-4X? ktjeittr t vvv v 5sin23)2( 23 +?+= ?  p/ ò T 0=t H¥′  1 t r d d v   2 t r d d v   3 t r r d d v v ?   4 t r r d d v v × b 3 (1) ktjeit t r t vvv v 5cos106)23( d d 22 +++= ?  0=t H  jr v v 3=  kji t r vvv v 1062 d d ++= (2) 1401062 d d 222 =++= t r v (3) 18)106()3( d d ?=+??=? kjj t r r vvv v v (4) ikjj t r r vvvv v v 30)106()3( d d ?=+×?=× 1