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3 s?1~0 2~1 s
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2
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t
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d
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a
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d
2
2
==
s2=t
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vv
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116 += jiv
vv
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(2) jijijirrr
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12
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D xà?_¥C? °== 4.63
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arctanθ
(3) ji
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32
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1-3 Bé? μ??F
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60cos2
22
22
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sin
=
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BA
v
vv
11
α
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v
v
1B
v
v
BA
v
v
°30
£1
v
v
/
£
v
v
/
£
v
v
/1
v
v
£1
v
v
β
α
3
£1/
£/1
vvv
vvv
+=
(1) °=== 60
10.1
55.0
arccosarccos
/
£
£1
v
v
α
s1050
60sin1.1
1000
60sin
10001000
=
°×
=
°
==
/
£/1
vv
t
(2) °=== 4.63
55.0
10.1
arctanarctan
£1
/
£
v
v
β
m500
10.1
1000
55.0
1000
=×=×=
/
£
£1
v
vx /?rá/3 ) b m500
3