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00
21
(sin sin ) (sin sin 30 )
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B
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μμπ
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120
0
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7
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2
3
02.04
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Z_<°??
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2
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4
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a
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0
12
(2 2 )
42
I
B tg
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R
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?
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3
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? s?
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l
a èEsY1 a è
@sY1 a b
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∴
l
l
R
R
I
I
1
2
1
2
2
1
== '
lIlI 2211
=
A
O
B
I
I
∴
I1
O?¥H??<
R
lI
R
l
R
I
B
2
11
01
1
0
1
422 π
μ
π
μ
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?_?
m 9-3
∴
I 2
O?¥H??<
R
lI
R
l
R
I
B
2
22
02
2
0
2
422 π
μ
π
μ
=?= Z_<° ??
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40
vDt ?
¨ i×?H?
' a vlM?Z_MQ b
B
v
1 B
v
2
∴ 0
20
1
=+=
B
B
B
v
v
v
9-4B??1 R¥
?? ???1 r¥|??s ({?è
?è?
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nm 9-4 b
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1
,ù R? rμ
I
11"$ip?"d¥H b
r
O
ω
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3
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r′d rrsq ′′?== d2dd πσσ
á
3¥è
@ qI d
2
d
π
ω
=
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2
d
2
d2
2
2
d
d
0
0
0
r
r
rr
r
I
B
′
=
′
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=
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π
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μ
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m 9-4
rr <′ ¥?sá
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00
0 22
r
r
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σ
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2
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2
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2
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2 ¥H vl Id rd
r
dI
rdPm
′
′
=
′
=
32
ωσππ
rr <′ ?s
3
0
1
4
r
m
dr
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4
r
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+
′==
′
∫
Z_
£ü_·
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4
1
443
rR
rd
rP
R
r
m
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∫
′
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?
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£ü_P
∴
RRRRrPPP mmm
44444
32
7
)
8
1
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4
1
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4
1
ωσπωσπωσπ ?=?=?=?=
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I
π2
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=
IE???)á
3¥H??<
a
ev
a
I
B
2
00
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μμ
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s
m
10
2.2
10
6.1
10
14.34
5.12)
10
53.0(14.344
16
197
10
2
0
2
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××××
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e
B
a
v
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41
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2
m
A
10
33.9
2
10
53.0
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a
a
ev
IS
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π
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ad" ef" 30cm be" cf" 30cm bp
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b
3
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v
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va
z
b
d
e
f
O
c
n
v
x
y
∴ Wb24.03.04.02
1
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BSSBΦ
vv
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U B
v
L,??
?
2B
v
ü??ü
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2
=°=?=
Φ
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m befc
vv
m 9-6
3,?ü
? abcd¥H ?L
?D, aefdü
? ¥H ?L
?M]
∴ Wb24.0
12
=?=
mm
ΦΦ
9-7
ü?é °?LM d" 40cm
? ??Lμ?
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@ I?m 9-7
?
U bp
1
?L
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x
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?
U
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r
1
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3
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3 y ?? m
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r
1
l
I
x P
d
I
r
3
r
2
1P?L P?¥H ??<
x
I
B
π
μ
2
0
1
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0
2
xd
I
B
?
=
π
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11
(
2
0
21
xdx
I
BBB
?
+=+=
π
μ
Z_<°?
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xl
xdx
I
SB
m
d)
11
(
2
d
d
0
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+=?=
Φ
π
μ
vv
∴ Wb102.2d)
11
(
2
d
60
21
1
?
+
×=?
?
+=?=
∫∫
rr
r
xl
xdx
I
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m
π
μ
vv
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p
9-8 ?m 9-8
?
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@ I
!è
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p
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b
b
a
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3
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p
ar < 02
11
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∫
r
B
ldB
L
π
vv
∴ 0
1
=
B
v
m 9-8
42
vDt ?
¨ i×?H?
bra << )(
)(
2
22
22
0
0
2 ar
ab
I
Ir
B
??
?
=′=? π
π
μ
μ
π
∴
)(2
)(
22
22
0
2
ab
r
ar
I
B
?
?
=
π
μ
Z_D I
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m
?èE5
br > Ir
B
μ
π
0
3
2 =? ∴
r
I
B
π
μ
2
0
3
= Z_D I
?@·
m
?èE5
2|
?í rrlS ddd ==
∴
a
b
ab
a
II
dr
r
ar
ab
I b
a
m
ln
)(24)(2
22
2
00
22
22
0
?
?=
?
?
=
Φ
∫
π
μ
π
μ
π
μ
9-9??1 R¥íKé????8=???B??1 r¥íKé??8
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b p
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@
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1??? 8àL¥H????1 r¥íKé??8?è
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3
m 9-9
R
r
O
O’
d
∴
r
rR
I
I
d
B
l
B
L
2
22
0
1
0
11
)(
2d π
π
μμπ ?
?
?==?=?
∫
v
v
)(2
22
2
0
1
rR
d
r
I
B
?
=
π
μ
2 b?? sàL
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@á
3
∴
d
rR
I
I
d
B
l
B
L
2
22
0
2
0
22
)(
2d π
π
μμπ ?
?
?==?=?
∫
v
v
)(2
22
0
2
rR
Id
B
?
=
π
μ
9-10?m 9-10
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U
í kvü?ü
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@
?è
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1
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2
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3 íkv e¥H??<vl
2
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1
i
v
2
i
v
1
e- W
e
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B x
v
v
2
1
0
1
μ
=
e
i
B x
v
v
2
2
0
2
μ
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∴
eiiBB
B
x
v
vv
v
)(
2
21
0
21
?=+=
μ
m 9-10
2·e -?
H
e
i
B x
v
v
2
1
0
1
μ
=
e
i
B x
v
v
2
2
0
2
μ
= ∴
eiiBB
B
x
v
vv
v
)(
2
21
0
21
+=+=
μ
Pe-?
H
e
i
B x
v
v
2
1
0
1
μ
?=
e
i
B x
v
v
2
2
0
2
μ
?= ∴
eiiBB
B
x
v
vv
v
)(
2
21
0
21
+?=+=
μ
43
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?
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á?¥ì?
?L5
? N Yμè
@ I ??
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1 R
1
? R
2
bp
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b
3
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v
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v
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R
1
R
2
NIrBlB μπ
0
2d =?=?
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vv
L
¤
r
NI
B
π
μ
2
0
=
b
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2??
?
|B z1 dr¥é H
?íHY
1
m 9-11
rb
r
NI
SBSB
m
d
2
dd
d
0
?==?=
Φ
π
μ
vv
∴
1
200
ln
2
d
2
Φ
2
1
R
RNIb
r
rNIb
R
R
m
π
μ
π
μ
==
∫
H?è
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v
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B
v
I
R
vl Z _·_?? dF IBdl=
2?? ? V?P??
s ?Z_
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2
cos cosdF IB Rd IBR
F
π
π
ααα
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==??=
∫∫P
m 9-12
3·??
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s ?1
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9-13 ??1 R ¥ü
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R
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v
s ?vl
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IIId
dF IBdl I Rd
R
μμα
α
π απ
′′
==? ?=?
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sH? ?Z_
£ü_P
∴
2
0
0
2
1
cos
22
II
dF d II
F
π
π
μ
ααμ
π
?
′
′== =
∫∫P
m 9-13
2·??
sH ?Z_
£ü_POD M?
FP
∴
0
2
II
FF
μ
′=
= P
44
vDt ?
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9-14B í K é
á
?e z1 a Y μè
@ I
1
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2
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1I
1
AB? CD)á
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á
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3 y ?? m
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a b c
D
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2
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1
1á
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x)| B z1 dx¥
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@
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a
=
dI AB)¥ H??<vl
0
2( )
AB
dI
d
B
abx
μ
π
=
+?
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3¥H?Z_M]
∴
11
00
0
ln
22
a
AB AB
dx a b
II
d
BB
aabx a b
μμ
ππ
+
== =
∫∫
+?
Z_< °?
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1
0
ln
2
CD
abc
I
B
abc
μ
π
++
=
+
Z_<°?
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2
12 12
00
ln ln
22
AB AB
AB AB
lab ab
II II
Idl dli i
FB
ab ab
μμ
ππ
++
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∫∫
v
v v
vv
] ?
12
0
ln
2
CD
l abc
II
i
F
abc
μ
π
++
=
+
v
v
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@ I
1
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1
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1 α L??Yμè
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2
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s¥ ?
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s¥ ? b
3
1bc? da
è
@ íZ_D B
v
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FFbc da
= =
v v
a
b
c
I
1
α
d
R
2
R
1
m 9-15
ab
I
1
1 r)|è
@í
2
dl
I
v
s ?
2
dF dl B
I
= ×
vv v
I
2
Q
2
dl B
I
⊥
v v
∴
12
0
2
2
II
dF dl B dr
I
r
μ
π
=?= Z_<°??
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2
1
12 12 2
00
1
ln
22
R
ab
R
dr
II II R
dF
F
r
R
μμ
ππ
== =
∫∫
] ?
12 2
0
1
ln
2
cd
II R
F
R
μ
π
= Z_<°??
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2 I
1
1 r)|B z1 dr¥
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2
1
2
S
r
α= ?
∴ dS rdrα=
H 1
22m
ddSr
PI I
dα== Z_<°??
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vDt ?
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H ? vl1
112
00
2
22
m
III
dM d B rdr dr
PI
r
αμμ
α
ππ
=?= ?=
∴
2
1
12 12
00
21
()
22
R
R
II II
Mdr
R R
ααμμ
ππ
==
∫
? Z__·
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v
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3
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10
2
m
MB NISB
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θ
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10
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v
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kp
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2?T¨???¥H ? b
30
0
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z
y
x
10cm
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v
5cm
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3
1| ??1 r z1 dr¥?ì è
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v
σ
<
O
R
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@
2
dI dq rdr
ω
ωσ
π
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H
23
m
ddI
Pr r
dπ πωσ==
m 9-17
4
0
4
1
d Rpp
R
mm
πωσ==
∫
Z_àL_
2
?
sH ? vl
m
p
3
mm
dM d B d B B dr
PP
πωσ=×=?=
v
v
Z_<° ?
?_ ú
∴
3
0
1
4
R
4
M dM B dr Bπωσ πωσ== =
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Z_< °?
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d
qv
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2
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sH ?vl
2
22
0
4 d
vq
qvBF
m
π
μ
== Z_·_
è? q'M o?
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sè? ?vl
2
0
2
4 d
q
F
E
πε
= Z__
è? q'M o?
1
11
2
2
2
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