Solution 2.9.2.4 f(t)=t[1(t;T); 1(t;2T)] Then F(s) = Lf(t;T)1(t; T)+T1(t; T)g;Lf(t ;2T)1(t;2T)+2T1(t;2T)g = Lf(t;T)1(t; T)g+ Lf(T1(t;T)g;Lf(t; 2T)1(t; 2T)g;Lf2T1(t; 2T)g = e ;Ts s 2 + Te ;Ts s ; e ;2Ts s 2 ; 2Te ;2Ts s = e ;Ts + Tse ;Ts ; e ;2Ts ; 2Te ;2Ts s 2 1