"
"
"
c
c
c
???5ccc ? ? ?MMMèèè
^
^
^3
?5.2?μ?? ó2￥ ?Mè
^.,,,,,,,,,,,,,,,,,,,,3
?5.2.15.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,3
?5.2.35.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,4
?5.2.45.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,5
?5.2.55.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,6
?5.2.65.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,7
?5.3?μ ??? ó2￥ ?Mè
^.,,,,,,,,,,,,,,,,,,8
?5.3.15.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,8
?5.4? ?M?
q.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,9
?5.4.35.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,9
?5.4.45.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,10
?5.4.55.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,11
1
List of Figures
155.2.1m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,3
255.2.1m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,4
355.2.3m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,4
455.2.4m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,5
555.2.5m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,6
655.2.6m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,7
755.3.1m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,8
855.3.1m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,8
955.4.3m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,9
1055.4.4m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,10
1155.4.4m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,10
2
5 ? ? ?MMMèèè
^
^
^
5.2μμμ?????? ó ó ó222￥￥￥ ? ? ?MMMèèè
^
^
^
5.2.1
?m1
U￥
^ ?M
1L?è
^è÷LèaUl = 380Vb ??èE?μ ó
??? èE1R1 = 11?R2 = R3 = 22?.(2) ?í??L pμMèa#
???èa;(3) ?í??L?L1M
^
H pòMèaè
@iS
ì￥
M
m.
[333]
m1:55.2.1m
(2)
!_U1 = U1\0– = 220\0–V
_UN0N =
_U1
R1 +
_U2
R2 +
_U3
R3
1
R1 +
1
R2 +
1
R3
=
220\0–
11 +
220\?120–
22 +
220\120–
22
1
11 +
1
22 +
1
22
V = 55\0–V
_U01 = _U1? _UN0N = (220\0–?55\0–)V = 165\0–V
_U02 = _U2? _UN0N = (220\?120–?55\0–)V = 252\?131–V
_U03 = _U3? _UN0N = (220\120–?55\0–)V = 252\131–V
(3) ?í??LL1M
^5òMμèa1
_U01 = 0
_U02 = _U21 =? _U12 = 380\?150–V
_U03 = _U31 = 380\150–V
3
òMμè
@1
_I2 = _U02
R2 =
380\?150–
22 A = 17:3\?150
–A
_I3 = _U03
R3 =
380\150–
22 A = 17:3\150
–A
_I1 =?( _I2 + _I3) =?(17:3\?150– +17:3\150–)A = 30\0–A
M
m ?m2
Ub
m2:55.2.1m
5.2.3
μB
?M?è  ?F ó???
M-?èa1220VbBQ
k
H¨èaV
¤MèaU1 = U2 = U3 = 220V7Lèa51U12 = U31 =
220V,U23 = 380V,
kù??C`
^ ?/?￥$
[333]
???è￥L1M ?F¤QèaM
m5 ?m3
Ub VnU12 = U31 =
m3:55.2.3m
220V,U23 = 380V.
4
5.2.4
m4(a)
U￥è
^? ?M
1L?è÷èa1380=220V¤μ??? ó
2￥a§μ 9?
q1180W.N?L3M
¤μ-?èa1220V,?
q140W,?
qy
cos’ = 0:5￥ °1§B|b
k pè
@_I1,_I2,_I3#_INb
!_U1 =
220\0–V.
[333]
!
m4:55.2.4m
_U1 = 220\0–V
_U2 = 220\?120–V
_U3 = 220\120–V
Ma§￥?
q
P = 13 ￡180W = 60W
Ma§￥è
@
I = PU
P
= 60220A = 0:273A
5
_I1 = 0:273\0–A
_I2 = 0:273\?120–A
_I03 = 0:273\120–A
°;§￥è
@
I003 = PU
P cos’
= 40220￡0:5A = 0:364A
5
ycos’ = 0:5,’ = 60–,_I0031_U3ìa60–,'1_U1? -60–,#¤
_I003 = 0:364\60–A
_I3 = _I03 + _I003 = (0:273\120– +0:364\60–)A
= 0:553\85:3–A
??Lè
@
_IN = _I1 + _I2 + _I03 + _I003
= _I003 = 0:364\60–A
èaè
@￥M
m ?m4(b)
Ub
5.2.5
m5(a)
^
Ms?è?
n?9c￥è÷sMè
^O
^M?L ?￥??
hb
k¨M
m
a
ü_U12_Uo3-W￥Mêμ190–b
[333]
?m5(a) Vn
m5:55.2.5m
_Uo3 = _U13? _U1o =? _U31? 1
2
_U12
= U1\?60–? 12Ul\0–
= Ul(cos60–?jsin60–)? 12Ul
=?j0:0866Ul = 0:866Ul\?90–V
6
5.2.6
m6(a)
^l?
q???èE?μV?Mè÷¤ ?M?èa￥è
^b
X?
MμèER = 10?,è÷
qf = 50Hz,
k p
3￥LC￥
′b
[333]
p3'5
H V5é?M
s7a9
b
m6:55.2.6m
?5i_U1a_U2a_U3
^ ?M?èa# V M
mb
Vm6(a)￥è
^m
 V¤
_UL = _U1? _U2 _UC = _U2? _U3
M
 ?m6(b)
U.
_ILìa?_UL 90–,_IC? -?_UC 90–,yNM
_IL_IC9 Vb7a_I2￥M
b
Vn
_Ua_ULa_UC?B? ???,#U = UL = UC;
_I2a_ILa_IC?B? ???,#I2 = IL = IC.
?
^
Up
3
R =
UL
XL =
UC
XC
p3R = X
L = XC
10p3 = 314L L = 10
p3
314 H = 0:055H = 55mH
10p3 = 1314C C = 1314￡10p3F = 184￡10?6F = 184?F
7
5.3μμμ ? ? ??????? ó ó ó222￥￥￥ ? ? ?MMMèèè
^
^
^
5.3.1
Lèa1380V￥ ?Mè÷
¤
FèE??μ ?m7
U
k p
Lè
@Ib
[333]
m7:55.3.1m
?? ó2
IlY = IpY = 22010 A = 22A
??? ó2
Ip￠ = 38038 A = 10A;Il￠ = p3Ip￠ = 10p3A
??_U1ìa?_U1230–,_IlYD_U1]M,_Ip￠D_U12]M,7_Il￠9ìa?_Ip￠30–,#_Il￠D_IlY
]M?
^
I = IlY +Il￠ = (22+10p3)A = 39:3A
èaDè
@￥M
m ?m8
Ub
m8:55.3.1m
8
5.4 ? ? ?MMM???
q
q
q
5.4.3
m9??μ ó? ???X?è÷èaUl = 220Vè
@V
Il =
17:3A, ?M?
qP = 4:5kW
k p(1)
Mμ￥èE? F (2)?L1L2M
7
Hm?òè
@V￥
9?
qP (3)?L1L 7
Hm?òè
@V￥
9?
qb
[333]
m9:55.4.3m
(1)Mè
@
IP = Ilp3 = 17:3p3 A = 10A
cos’ = Pp3U
lIl
= 4:5￡10
3
p3￡220￡17:3 = 0:683
jZj = UpI
p
= 22010? = 22?
R = jZjcos’ = 22￡0:683? = 15?
XL = jZjsin’ = jZj
p
1?cos’2 = 22￡p1?0:6832? = 16:1?
(2)?L1L2M 7
H
I1 = I2 = 10A I3 = 17:3A P = 3kW
(3)?L1L 7
HZ12DZ311 óèa_U23
 ?
@Vè
@1102 A =
5A, ODL2L3M?￥è
@(10A)]M?
^¤
I1 = 0 I2 = I3 = (5+10)A = 15A
9?
q
P = I2pR +(12Ip)2 ￠2R = (102 ￡15+52 ￡2￡15)W = 2250W
9
5.4.4
m10
U￥è
^?è÷LèaUl = 380V
qf = 50Hz?è?
?μ￥?
qP = 10kW?
qy
cos’1 = 0:5b1
|L
^?
qy
4ú
?cos’ = 0:9
kù
m?
Mi ó￥?êè ? ￥è ?′ò1
$?¨
'
? ó2
?????Z
T?z$
[333]
?m11
U￥?
q ??? V?
3?êè ? ￥í??
q1
m10:55.4.4m
m11:55.4.4m
Q = P tan’1?P tan’ = P(tan’1?tan’)
(1)è ?  ??? ó2
@Vè ? ￥Mè
@1
Ipc = !CUl
10
Lè
@
Ilc = p3Ipc = p3!CUl
è ? ￥í??
q1
Q = p3UlIlc = p3Ulp3!CUl = 3!CU2l
?
^¤
Mè ? ￥è ?
C = Q3!U2
l
'5?
cos’1 = 0:5;’1 = 60–;tan’1 = 1:73
cos’ = 0:9;’ = 26–;tan’ = 0:48
Q = P(tan’1?tan’) = 10￡103(1:73?0:48)var = 12:5￡103var
?N¤
C = Q3!U2
l
= 12:5￡10
3
3￡314￡3802F = 92￡10
6F = 92?F
(2)è ? ?? ó2
D(1)?]?m10(b)?
Mè ? 
F￥
^è÷MèayN
Mè
?
C = Q3!U2
p
= 12:5￡10
3
3￡314￡2202F = 274￡10
6F = 274?F
¨è ?
1 ??? ó2
H1v ?#4ú ?Mè??è
^￥?
qy
Hè ? è ó2? ???b
5.4.5
?TèaM?
{
?
qM?  ?M?L
^?
q
{M?5 ?M
{è
L
!μ?￥¨^
1?M
{èL￥¨^
￥34b
k￡
ü-b
[333]
y1
{
?
qM?'
p3U
3I3 cos’ = U1I1 cos’
5¤
I1 = p3I3
11
y1L
^?
q
{M?'
3I23R3 = 2I21R1
5¤
R1 = 12R3S1 = 2S3
yN¨^
-11
(¨^
)3
(¨^
)1 =
3S3l‰
2S1l‰ =
3
4

ò
T?R
^
?
{èL￥èES
^
{èL￥?
l
^
{èL￥é
‰
^?L?
￥
áb
12
13