电工学答案（秦曾煌）：dz14

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???14ccc===555???8885553
?14.3?=5.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,3
?14.3.25.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,3
?14.3.55.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,4
?14.4?×a=5.,,,,,,,,,,,,,,,,,,,,,,,,,,,5
?14.4.25.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,5
?14.5??85.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,5
?14.5.15.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,5
?14.5.35.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,6
?14.5.45.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,7
1
List of Figures
1514.3.2m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,3
2514.3.2m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,3
3514.3.5m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,4
4514.4.2m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,5
5514.5.3m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,6
6514.5.4m.,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,7
2
14===555???888555
14.3===555
14.3.2
m1
U￥òè
^m?
E = 5V
ui = 10sin!tV
=5D￥?_a?
V-
{?9

ksY
{èau0￥o?b
[333]
m1:514.3.2m
(a) ui1???
H
ui > E
D?Y
ui < E
D??bui1μ??
H
D?
?b
D?Y
H
u0 = E
D??
H
uo = uib
(b) ui1???
H
ui > E
D?Y
ui < E
D??bui1μ??
H
D?
?b
D?Y
H
u0 = ui
D??
H
u0 = Eb
u0￥o?sY?m2(a)(b)
Ub
m2:514.3.2m
3
14.3.5
m3?

kp/
+?f ?/
{
èêVY#òíq?YV￥è
@b(1)VA =
+10V
VB = 0V
(2)VA = +6V,VB = +5:8V;(3)VA = VB = +5V.
!=5￥?
_èE1
,
Q_èE1íkvb
[333]
m3:514.3.5m
(1)=5DAa5?Y
5
VY = 9￡ 101+9V = 9V
IDA = IR = VYR = 99￡103A = 1￡10?3A = 1mA
DBQ_
ê?
??
IDB = 0
(2)
!DADB
5??Y
?¨2?èaE9
VY

VY =
6
1 +
5:8
1
1
1 +
1
1 +
1
9
V = 11:8￡919 V = 5:59V < 5:8V
VnDB59?
?Yb
IDA = 6?5:591￡103 A = 0:41￡10?3A = 0:41mA
IDB = 5:8?5:591￡103 A = 0:21￡10?3A = 0:21mA
IR = 5:599￡103A = 0:62￡10?3A = 0:62mA
4
(3) DADB
5?
?Y
VY =
5
1 +
5
1
1
1 +
1
1 +
1
9
V = 4:74V
IR = VYR = 4:749￡103A = 0:53￡10?3A = 0:53mA
IDA = IDB = IR2 = 0:532 mA = 0:26mA
14.4×××aaa===555
14.4.2
μ
?×a=5DZ1DZ2
×?èasY15:5V8:5V
?_a??
^0:5Vb?T1¤?3V￥×?èa
?? ?¤
$
[333]
??m4(a)(b) ?¤
UZ = 3Vbm?R1aR2
^K
@èEb
m4:514.4.2m
14.5???888555
14.5.1
μ
??85sY¤è
^?
??¤
ì5?￥èê

\1"
sY?
/V


?85I
5?1 2 3
èê/V 4 3:4 9
?85II
5?1 2 3
èê/V?6?2:3?2
k
Y50￥??è
i
a
ü
^A5
^?5
$
^NPN?
^PNP?
$
[333]
5
NPN?
"èèêKú
?
èêK?
UBE > 0
PNP?
?
èê
Kú
"èèêK?
UBE < 0b
A5
èêD?
èêv?Mμ0:6V0:7V
?5
èêD?

èêv?Mμ0:2V0:3Vb
?N V?

?85I
NPN?
A5
1?Ba2?Ea3?C

?85II
PNP?
?5
1?Ca2?Ba3?Eb
14.5.3
?¨￡¨V
B??85
^NPN?
^PNP?
$?
50
￥??5?
$?5A5??YV
LuY ?
$
[333]
(1)5

|??￡¨V\-"

L1V
=è÷?
? d￥?
k3
}
@¤?B5?

7a|
6B?
k3sY¤
6?
?5?
?T
Q?¤5?W￥èE]
1?èE

BEWBCW￥PN2
F?_èa
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W￥PN2
FQ_èa

5¤￡¨V\-"? d￥
^b
(2)

^NPN?5
^PNP?5
(1)?
?¤5?W￥èE]1?èE
H
51NPN?5
?¤]1ú
èE
H
51PNP?b
(3)
"è
X?￥NPN?5PNP?5vm5
U￥
?ZE¤L
??5
m5:514.5.3m
?12¨?
k3sY¤￡¨V￥\+"
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?i
\-"? d¤V
=è
6
÷￥?

1?
?¤E1
25?W￥èEú?bNPN?5
èE
??
H¤\-"? d￥
^"è
PNP?5
èE??
H¤\+"? d￥
^
"èb
(4)

^?5
^A5
B
EW?_a?0:6? 0:7V
H1A5
0:2? 0:3V
H1?5b
14.5.4
m6:514.5.4m
m6
U￥ò?è
^?

kù?85yT??

$
!UBE = 0:6Vb
[333]
9
2Tn/Vb
(a)5(b)5(c)5
IC(sat) … UCCR
C
12mA 8mA
I0B = IC(sat)fl 0:24mA 0:2mA
IB 6?0:650 mA = 0:11mA 12?0:647 mA = 0:24mA IB < 0

IB < I0BbvIB > I0B??
7
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