Solution 2.9.5.8 Applying the Laplace transform yields s 2 Y (s);sy(0);y [1] (0);4Y (s)=0: Rearranging yields (s 2 ;4)Y (s)=sy(0) + y [1] (0);; or Y (s)= sy(0) + y [1] (0) (s;2)(s +2) For the given initial conditions we then have Y (s) = s ;2 (s +2)(s;2) = 1 s +2 : y(t)=e ;2t 1(t) 1