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2005-11-25
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2005-11-25
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2005-11-25
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2005-11-25
4
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2005-11-25
5
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2?t bt?vD
2005-11-25
6
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=++== IZIIU
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2?t bt?vD
2005-11-25
7
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bbaakbakbakk
)(2
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2121
2
222
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21
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Z
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2?t bt?vD
2005-11-25
8
0 ,0)]([
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2122112222
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2?t bt?vD
2005-11-25
9
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2005-11-25
10
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2005-11-25
11
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2005-11-25
12
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2005-11-25
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2005-11-25
)(
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2005-11-25
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2?t bt?vD
2005-11-25
16
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2005-11-25
17
?a è#)
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2?t bt?vD
2005-11-25
18
3)
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2005-11-25
19
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2005-11-25
20
?73 .
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p
n
p
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2005-11-25
21
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11
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1
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sZ
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11
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11
(s)=D
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11
21
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sH
sss
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sH
p
n
p
=
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666 L
2?t bt?vD
2005-11-25
22
1
LC
T (*)￥èaMf
? H(s) V[¨
LC?
a￥|??E Ff
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2?t bt?vD
2005-11-25
23
ê Z
11
(s)￥s0 =H(s)￥s
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11
(s)￥s
Z
11
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Cauer II
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11
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ZE
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[s p=0ap=n? 0<p<n ? I
nb
2?t bt?vD
2005-11-25
24
L
! p=0
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)(
0
21
0
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H
sss
H
sH
n
=
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=
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?¨ Cauer I ?
LC 8?
RC|??E F Z
11
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μ i óD1è ? ?"
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è 1
2?t bt?vD
2005-11-25
25
3
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2
45
2
)(
2
++
=
++
=
ssss
sH
Z
11
V[μ ??]￥ê4?
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^
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2
21
+
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Z
H(s)￥ 2?.
{
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11
(s)
2?t bt?vD
2005-11-25
26
s
s
ss
ss
Z
4
2
1
2
1
1
1
3
45
2
2
11
+
+
+=
+
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=
1$
2$
1
U F
4
1
+
+
?
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2
U
F
2
1
11
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g0?è
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45
4
)(
2
++
=
ss
sH
2?t bt?vD
2005-11-25
27
?@ó? H(s)￥1 pb?s0MμB?1 èy0b¨
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^ ?
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HB???C??
f ?b ?1¤
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n
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Cauer II ?
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H 1 óD1è ?
i óD1èE y7 ?1?á
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{
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2?t bt?vD
2005-11-25
28
¨ RC0?è
^
LCèaMf
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45
)(
2
2
0
++
=
ss
sH
sH
è 2
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11
+
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ss
Z
H(s)￥
?μ.
{
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¨ Cauer II ?
L
C
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11
(s)
2
11
6
121
1
11
9
1
3
4
3
45
2
2
11
+
+
+=
+
++
=
s
sss
ss
Z
3
2?t bt?vD
2005-11-25
29
1
U
F
4
3
+
+
??
2
U
?
9
11
11
Z
F
121
6
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2
11
45
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2
2
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s
sH
H(s)￥ nD p-W1 0<p<n
H￥ f ?b s = )? s = ?
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11
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T ???b
2?t bt?vD
2005-11-25
30
¨ RC0?è
^
LCèaMf
?
45
)(
2
0
++
=
ss
sH
sH
è 3
ó?￥ H(s) s = )? s = ?)sYμB?.
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)3(
)4)(1(
11
+
++
=
ss
ss
Z
5¨ Cauer I ?
LC s = ?)￥.
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,?
R
Z
s
s
s
ss
ss
Z
1
2
1
1
1
2
4
1
2
1
1
1
3
45
2
2
11
+
+=
+
+
+=
+
++
=
3
2?t bt?vD
2005-11-25
31
s
s
Z
R
42 +
=
?
HXüμB?i óè ? ?á
3B?.
{
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:?
￥|??E Ff
? Z
R
¨ Cauer II ?Z 7
LC
1$
1
U
+
?
F
2
1
11
Z
R
Z
2
42442
+=
+
=
+
=
ss
s
s
s
Z
R
2?t bt?vD
2005-11-25
32
1$
2$
1
U
F
4
1
+
+
?
?
2
U
F
2
1
11
Z
R
Z
45
2
)(
2
++
=
ss
s
sH
2?t bt?vD
2005-11-25
33
3
5¨ Cauer II ?
LC s = )￥.
{
,?
R
Zs
ss
ss
s
ss
ss
ss
ss
Z
+=
+
+
+=
+
++
=
+
++
=
3
4
3
3
11
3
4
3
54
3
45
2
2
2
2
2
2
11
1
U
+
?
11
Z
R
Z
F
4
3
2
2
3
3
11
ss
ss
Z
R
+
+
=
2?t bt?vD
2005-11-25
34
N Z
R
s = ?)1μK′
¨ Cauer I ?
LC Z
R
9
2
1
2
3
1
1
3
3
11
3
3
11
2
2
2
2
+
+=
+
+
=
+
+
=
s
ss
ss
ss
ss
Z
R
1
U
F
4
3
+
+
??
2
U
?
9
2
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2?t bt?vD
2005-11-25
35
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2005-11-25
36
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2005-11-25
37
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2005-11-25
38
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2005-11-25
39
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2005-11-25
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2005-11-25
41
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2005-11-25
42
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2005-11-25
43
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2005-11-25
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2005-11-25
45
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2005-11-25
46
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2005-11-25
47
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2005-11-25
48
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2005-11-25
49
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2005-11-25
50
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2005-11-25
51
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2005-11-25
52
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2005-11-25
53
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2005-11-25
54
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2005-11-25
55
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2?t bt?vD
2005-11-25
56
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2005-11-25
57
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2?t bt?vD
2005-11-25
58
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2005-11-25
59
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2005-11-25
60
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2005-11-25
61
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2005-11-25
62
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2005-11-25
63
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2005-11-25
64
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2005-11-25
65
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2005-11-25
66
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2005-11-25
67
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2005-11-25
68
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2005-11-25
69
122
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2005-11-25
70
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2005-11-25
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2005-11-25
74
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2005-11-25
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2005-11-25
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2005-11-25
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s
s
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i
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2005-11-25
81
? tc T<
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2
0
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p RC?
?i p H
0
￥′b
7-2
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)(
0
+++
=
sss
H
sH
p RC?
?i p H
0
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)(
21
0
==
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= RR
sss
sH
sH
7-3
p RC?
?i p H
0
￥′b
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0
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=
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sH
7-4
p RC?
?i p H
0
￥′b
2?t bt?vD
2005-11-25
82
7-5
158
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2
2
0
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++
=
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sH
p RC?
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7-6
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)(
222
4
0
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=
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sH
sH
p LC?
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7-7
324
)(
234
0
++++
=
ssss
sH
sH
μèE R
2
= 1$
k p LC?
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324
)(
234
0
++++
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ssss
sH
sH7-8
R
1
= 1$
k p LC?
?
2?t bt?vD
2005-11-25
83
122
)(
23
3
0
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=
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7-9
μèE R
1
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2
= 1$
k p LC?
?b
南京航空航天大学：电网络理论：第七章
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