Lecture 2: The nucleus and nuclear instability Nuclei are described using the following nomenclature: N A Z Element Z is the atomic number, the number of protons: this defines the element. A is called the “mass number” A = N + Z. N is the number of neutrons (N = A - Z) Nuclide: A species of nucleus of a given Z and A. Isotope: Nuclides of an element (i.e. same Z) with different N. Isotone: Nuclides having the same N. Isobar: Nuclides having the same A. [A handy way to keep these straight is to note that isotope includes the letter “p” (same proton number), isotone the letter “n” (same neutron number), and isobar the letter “a” (same A).] Example: 122 206 84 124 207 83 126 208 82 124 206 82 Po ofisobaranand Bi ofisotoneanis Pb ofisotopeanis Pb 1 Chart of the Nuclides Image removed. 90 natural elements 109 total elements All elements with Z > 42 are man-made Except for technicium Z=43 Promethium Z = 61 More than 800 nuclides are known (274 are stable) “stable” unable to transform into another configuration without the addition of outside energy. “unstable” = radioactive Images removed. [www2.bnl.gov/ton] 2 Nuclear Structure: Forces in the nucleus Coulomb Force Force between two point charges, q, separated by distance, r (Coulomb’s Law) 2 210 )( r qqk NF = k 0 = 8.98755 x 10 9 N m 2 C -2 (Boltzman constant) Potential energy (MeV) of one particle relative to the other r qqk MeVPE 210 )( = Strong Nuclear Force ? Acts over short distances ? ~ 10 -15 m ? can overcome Coulomb repulsion ? acts on protons and neutrons Image removed. Fig 3.1 in Turner J. E. Atoms, Radiation, and Radiation Protection, 2 nd ed. New York: Wiley-Interscience, 1995. 3 Summary of Nuclear Forces: Nuclei give off energy (i.e., radiation) in an attempt to become more stable Nuclear instability can be traced to the interaction of i) Coulomb and ii) strong nuclear force. Coulomb Strong Nuclear repulsive attractive p + - p + p + - p + , n - n , p + - n doesn't saturate short range; falls off quickly weak (eg. e - to nucleus, very strong (several decades of MeV) ~ few eV to .1 MeV) atom is mostly empty space nucleus is densely packed Due to the Coulomb-nuclear force balance, nuclei exhibit a roughly constant density and radius. 4 Energy-Mass Equivalence Atomic Mass Units (amu, or AMU) By definition: Atomic masses are measured on a scale in which a 12 C 6 atom is exactly 12 atomic mass units. Gram atomic weight of any element contains N 0 atoms (N 0 = Avogadro's number). 12 grams of carbon = 6.02 x 10 23 carbon atoms kgxgx gX amu AMU atomcarbon gx atomsx carbong 2724 23 23 23 1066.11066.1 12 1099.1 1 12 1099.1 1002.6 12 ?? ? ? === == Using Einstein’s mass-energy equivalence formula: E=m o c 2 , 1.660531 x 10 -27 kg x (3.0 x 10 8 m/s) 2 = 1.49448 x 10 -10 kg m 2 /s 2 = 1.49448 x 10 -10 Joule Given: 1.6022 x 10 -19 Joules = 1 eV 1 AMU is equivalent to 931.48 MeV Rest mass energies and mass equivalences: electron mass: 0.000549 amu = 0.511 MeV proton mass: 1.007277 amu = 938.28 MeV neutron mass: 1.008665 amu = 939.57 MeV hydrogen atom: 1.007825 amu 5 Mass Differences, ? The mass of a nuclide is LESS than the sum of its parts… ? Energy released when all constituents come together. ? Nuclear force so strong that the mass of the bound system is smaller than the sum of the components. ? = M - A, or M = ? + A M is the true atomic mass A is the atomic number Image removed. Appendix D in [Turner] 6 Nuclear reactions release energy γ 0 0 2 1 1 1 1 0 +→+ HHn How much energy is released? Compare the total masses on both sides of the arrow. 7 Nuclear Binding Energies The difference in mass between a given nucleus and the sum of the same number of individual protons and neutrons is the binding energy. Image removed. Fig 3.3 in [Turner] 8 Nuclear Stability/Instability ? Strong nuclear force, operates over short range ? “saturates” quickly ? neutrons interact only with neighbors ? protons interact (repulse via Coulomb interaction) throughout the entire nucleus. In heavier nuclei, the #neutrons must increase faster than the number of protons to maintain stability. ? N/Z ratio = 1 at low A ? e.g., Mg Z=12, but N=12,13 or 14 (isotopes) ? N/Z ratio approaches 1.5 when Z~80 “Line of stability” Z = N Any nucleus far from the “line of stability” will be unstable. The position of a nucleus relative to the line of stability will define the mode of nuclear instability (radioactive decay mode). Image removed. Radioactive decay tends towards the line of stability Image removed. 9 Alpha decay Natural alpha emitters: Z > 83 QHeDP A Z A Z ++→ ? ? 4 2 4 2 ? conservation of electric charges ? conservation of nucleons E.g., HeRnRa 4 2 222 86 226 88 +→ How much energy, Q, is released? Compare the masses on both sides of the arrow. Q = M Ra – M Rn - M He Use ? values in Turner Appendix D. Q = ? Ra - ? Rn - ? He Q = 23.69 - 16.39 - 2.42 = 4.88 MeV 10 How is this energy, Q, distributed? Shared by the daughters, the Rn nucleus and the alpha particle. ? Momentum is conserved: mv = MV ? Kinetic energy of the 2 products = Q QMVmv =+ 22 2 1 2 1 The energy of the alpha particle: Mm MQ mvE + == 2 2 1 α The energy of the Rn nucleus: Mm mQ MVE N + == 2 2 1 Alpha decay results in a 2-particle emission. Q is fixed by the mass balance E α is fixed by the conservation laws (energy, momentum) Therefore, alpha particles must have discrete energies. 11 Nuclear Decay Scheme Diagrams Graphical display of nuclear transformations ? Decay mode ? Energy transitions ? Abundances (branching ratios) Image removed. Fig. 3.4 in [Turner] Conventions: ? Arrows slanting to the left indicate decrease in Z ? Arrows slanting to the right indicate an increase in Z ? Wavy lines going straight down indicate a gamma emission from the nucleus. Image removed. Appendix D in [Turner] 12 Decay Scheme Exercise HePoRn 4 2 215 82 219 86 +→ α 6.82 (80%) 6.55 (12%) 6.42 (7%) γ 0.271 (10%) 0.402 (7%) 13