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V¨?lp/
s
(1) Rba xdx(0 < a < b)
(2) Rba kdx(k
^è
?
(3) R2?1 x2dx
(4) R10 axdx(a 6= 1;a > 0).
2
!f(x)[a+c;b+c] V£
üf(x+c)[a;b]
VO
Z b
a
f(x+c)dx =
Z b+c
a+c
f(x)dx:
3
!
f(x) =
8
<
:
1;x = c;c 2 (a;b);
0;x 2 [a;c)[(c;b];
p£Rba f(x)dx = 0.
4?f
?f(x)[a;b]
Vs
^I?[a;b]=μK??
?
Mf(x)¥′
P
??1
6Bf
?f?(x)£
üf?(x)9[a;b]
ViO
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x2?s¥'?é
1.
!f(x)[a;b] ??f(x) ? 0f(x)??1
,£
ü
Z b
a
f(x)dx > 0:
1
2.
!f(x)[a;b] ??Rba f2(x)dx = 0£
üf(x)[a;b]
?1
,.
3. è
a
üf2(x)[a;b] V?f(x)[a;b]? V.
4.1?/
ò?s¥vl
(1) R10 xdx , R10 x2dx
(2) R
…
20 xdx,
R …
20 sinxdx
(3) R?1?2 (13)xdx, R10 3xdx .
5£
ü/
??
T
!
?ó¥si
(1) 1 ?R10 ex2dx ? e
(2) 1 ?R
…
20 sinx
x dx ?
…
2
(3)…2 6R
…
20 dxp
1?12 sin2 x 6
…p
2
(4) 3pe ?R4e0 lnxdxpx ? 6.
6£
ü
(1) limn!1R10 xn1+xdx = 0
(2) limn!1R
…
20 sinn xdx = 0.
7
!f(x);g(x)[a;b] ??£
ü
lim
?!0
nX
i=1
f(?i)g( i)¢xi =
Z b
a
f(x)g(x)dx
?a = x0 < x1 < ¢¢¢ < xn = b;¢xi = xi ? xi?1;?i; i 2 [xi?1;xi](i =
1;2;¢¢¢ ;n);? = max1?i?nf¢xig.
2
8.
!f0(x)[a;b] ??Of(a) = 0p£
flfl
flfl
fl
Z b
a
f(x)dx
flfl
flfl
fl?
(b?a)2
2 maxa?x?b
flflf0(x)flfl:
9.
!0 < – < 1p£
limn!1
R1
– (1?t
2)ndt
R1
0 (1?t2)ndt
= 0:
10(1)
!f(x)[a;b]
??O[a;b]
?B ??f
?g(x) (
μRba f(x)g(x)dx = 0£
üf(x) · 0;x 2 [a;b].
(2)
!f(x)[a;b]
??O
?μ*t[a;b]
?@?FHqg(a) =
g(b) = 0¥ ??f
?g(x)μRba f(x)g(x)dx = 0.£
ü[a;b]
]"
μf(x) · 0.
11
!f(x);g(x)[a;b] ??p£
flfl
flfl
fl
Z b
a
f(x)g(x)dx
flfl
flfl
fl?
sZ
b
a
f2(x)dx¢
sZ
b
a
g2(x)dx
7O?|? ??O??g(x) = ?f(x)(f(x) = ?g(x))??1è
? b
12.
!f(x);g(x)[a;b] ??p£
sZ
b
a
[f(x)+g(x)]2dx ?
sZ
b
a
f2(x)dx+
sZ
b
a
g2(x)dx
7O?|? ??O??g(x) = ?f(x)(? ? 0è
?).
13.
!f(x)[0;1] ??f(x) ? fi > 0p£
Z 1
0
1
f(x)dx ?
1R
1
0 f(x)dx
:
14.
!y = ’(x)(x ? 0)
^?ì??9F¥ ??f
?’(0) = 0;x =
`(y)
^
?¥Qf
?£
ü
Z a
0
’(x)dx+
Z b
0
`(y)dy ? ab(a ? 0;b ? 0):
3
15.¨Bá ???l£
(1) f(x) = 3px[0;1]
^Bá ??¥
(2) f(x) = sinx(?1;+1)
^Bá ??¥
(3) f(x) = x2[a;b]
Bá ???(?1;+1)
?Bá ??
(4) f(x) = sinx2(?1;+1)
?Bá ??.
x3±s'? ?
1.9
?/
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(1) R…0 cos2 xdx
(2) Ra0 pa?xdx
(3) R…0
p
1?sin2 xdx
(4) R?3?4 dxxpx2?4
(5) R21 lnxx dx
(6) Re1
e
jlnxjdx
2p/
K
(1) limn!1
nP
k=1
1
n sin
k…
n
(2) limn!1?1n + 1n+1 +¢¢¢+ 12n¢
(3) limn!1
nP
k=1
k
n2
(4) limn!1 1n npn(n+1)¢¢¢(2n+1)
3?f(x) ??pF0(x)
4
(1) F(x) = Rx20 f(t)dt
(2) F(x) = Rbx f(t)dt
(3) F(x) = Rx3x et2dt
4p/
K
(1) limn!1
Rx
0 cost
2dt
x
(2) limn!1
?Rx
0 e
t2dt
·2
Rx
0 e
2t2dt
5
!f(x)[0;+1) ??O???9p£f
?
F(x) = 1x
Z x
0
f(t)dt
(0;+1)
??O???9 b
x4?s¥9
?
1.9
?/
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(1) R21 (x+1)(x2?3)3x2 dx
(2) R10 x2+1x4+1dx
(3) R
1
5
?15 x
p2?5xdx
(4) R94 (px+ 1px)dx
(5) R10 p4?x2dx
(6) Ra0 x2pa2 ?x2dx
(7) R
…
20 sinmxcosnxdx
(8) R10 dx(x2?x+1)3=2
5
(9) R30 xdx1+p1+x
(10) R40 x(x+px)dx
(11) R
…
21 cosx
1+sin2 xdx
(12) R10 e
px
dx
(13) R10 xarctanxdx
(14) R2…0 x2 cos2 xdx
(15) R…?… x2 cos2 xdx
(16) R
pln2
0 x
3e?x2dx
(17) R…?… sinmxcosnxdx
(18) Ra0 x2
q
a?x
a+xdx(a > 0)
(19) R2a0
px2?a2
x4 dx
(20) R
1p
5
0 x3(1?5x2)10dx
29
?/
?s
(1) R
…
20 sin9 xdx
(2) R…0 sin5 xdx
(3) R2…0 cos6 xdx
(4) R
3…
20 cos7 xdx
(5) Ra0 (a2 ?x2)ndx
(6) R10 (1?x2)6dx
6
3£
ü ??¥f
?¥BMef
?¥1}f
? ??¥}f
?¥e
f
??μOoμB?1f
?.
4
!f(x)
?
UuW
^ ??f
?£
ü
(1) R
…
20 f(sinx)dx =
R …
20 f(cosx)dx
(2) R…0 xf(sinx)dx = …2 R…0 f(sinx)dx
(3) Ra1 f(x2 + a2x2)dxx = Ra21 f(x+ a2x )dx2x
(4) Ra0 x3f(x2)dx = 12 Ra20 xf(x)dx(a > 0)
59
?sR …20 sinxcosx+sinxdx.
6 ?¨s?sE£
ü
Z b
a
f(u)(x?u)du =
Z x
0
(
Z u
0
f(x)dx)du:
7.
!f00(x)[a;b] ??Of(a) = f(b) = 0p£
(1) Rba f(x)dx = 12 Rba f00(x)(x?a)(x?b)dx
(2)
flfl
flRba f(x)dx
flfl
fl? (b?a)312 maxa?x?bjf00(x)j
8
!f(x)x > 0
H ???ia;b > 0s′
Z ab
a
f(x)dx
Daí1p£f(x) = cx
c1è
?.
9
!f(x)?BμKuW
VsO
limx!1f(x) = l
p£
limx!1 1x
Z x
0
f(t)dt = l
7
x5?st ??¥?¨?
1.μB
?x2a2 + y2b2 ? 1(a > b)éà#°Z_B???
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£
e¥a ?.
2.?yvBB
H15/?? b
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1.X?R10 dx1+x2 = …4
küsuW[0;1]s?10?ssY¨0?
T
??tL
T9
?…¥í
?′ú??l
??a?ê.
2.üsuW10?s¨?tL
T9
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s¥í
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(1) R10 p1?x3dx (2) R21 dxx .
8