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(1) R+12 1x2?1dx;
(2) R+11 dxx(1+x2);
(3) R+10 xe?ax2dx(a > 0);
(4) R+10 e?ax sinbxdx(a > 0);
(5) R+10
px
1+x2dx;
(6) R+10 dx(x2+p)(x2+q)(p;q > 0):
2)
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l ??:
(1) R+10 dx3px4+1;
(2) R+11 xarctanx1+x3 dx;
(3) R+11 sin 1x2dx;
(4) R+10 dx1+xjsinxj;
(5) R+10 x1+x2 sin2 xdx;
(6) R+10 xm1+xndx(n;m > 0);
(7) R+10 x2dxx4?x2+1;
(8) R+11 dxx 3p1+x2;
(9) R+10 xpe?xdx;(p ? 0);
1
(10) R+11 lnxxp dx;
(11) R+11 lnn xx2 dx(n);
(12) R+10 sin2 xx dx;
(13) R+10 cosax1+xn dx;
(14) R+11 [ln(1+ 1x)? 11+x]dx;
(15) R+11 ln(cos 1x +sin 1x)dx;
(16) R+10 1x2 ln(1? sin2 x2 )?1dx:
3)
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l ?Hq
l ?):
(1) R+11 cos2 xx dx;
(2) R+11 cosxx dx;
(3) R+11 cosxxp dx;
(4) R+10
pxcosx
x+100 dx;
(5) R+12 lnlnxlnx sinxdx:
4
!f(x) ? h(x) ? g(x);a ? x < +1;h(x)?iμKuW[a;A] V
,?R+1a f(x)dx?R+1a g(x)dx
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6?f(x)[a;+1)
??/?,OsR+1a f(x)dx
l ?,p
£: limx!+1xf(x) = 0:
7
!f(x)[0;+1)
Bá ??,iOsR+10 f(x)dx
l ?,£
ülimx!+1f(x) = 0.?T????sR+10 f(x)dx
l ?,[#f(x)[a;+1) ?
2
?,f(x) ? 0,
^?ˉμlimx!+1f(x) = 0?
8
!R+1a f(x)dxDR+1a f0(x)dx
l ?,p£:
limx!+1f(x) = 0:
9
!f(x)??/?t?
,,f0(x)[0;+1) ??.p£:
Z +1
0
f0(x)sin2 xdx
l ?.
10
!f(x)?g(x)
^?l[a;+1)
¥f
?,O??
μKuW[a;A]
V,£
ü:?R+1a f2(x)dxDR+1a g2(x)dx
l
?,5R+1a [f(x)+g(x)]2dxDR+1a f(x)g(x)dx9
l ?.
11£
ü: (1)
!f(x)[0;+1) ??,Olimx!+1f(x) = k,5
Z +1
0
f(ax)?f(bx)
x dx = [f(0)?k]ln
b
a (b > a > 0):
(2)?
?Hqlimx!+1f(x) = k?1R+1a f(x)x dxi(a > 0),5
Z +1
0
f(ax)?f(bx)
x dx = f(0)ln
b
a (b > a > 0):
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l ?p′.
(1) R
1
20 cotxdx;
(2) R10 lnxdx :
3
(3) Ra0 dxpa?x;
(4) R10
q x
1?xdx:
2)
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l ??:
(1) R10 sinxx3
2
dx;
(2) R10 dx3px2(1?x);
(3) R10 lnx1?x2dx;
(4) R
…
20 dx
sin2 xcos2 x;
(5) R10 jlnxjpdx;
(6) R
…
20 1?cosx
xm dx;
(7) R10 dxlnx;
(8) R…0 dxpsinx;
(9) R10 xfi lnxdx;
(10) R10 xp?1?xq?1lnx dx;
(11) R
…
20
ptanxdx;
(12) R
…
20 cosxlnsinxdx:
3?Y
l ??:
(1) R+11 ln(1? 1x2)?1dx;
(2) R+10 xp?1e?xdx;
(3) R+10 (arctanx)qxp dx;
4
(4) R+10 ln(1+x)xp dx;
(5) R+11 dxxp lnq x;
(6) R+10 dxxp+xq;
(7) R+10 dx3px(x?1)2(x?2);
(8) R0?1ex lnjxjdx:
4)
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l ??D '
l ??:
(1) R+10 sinx2dx;
(2) R+10 sinp xxq dx;
(3) R+10 xp sinx1+xq dx(q ? 0);
(4) R+10 sin(x+1x)xn dx:
59
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<s¥′:
(1) R10 (lnx)ndx;
(2) R10 xnp1?xdx:
6£
üsA = R
…
20 ln(sinx)dx
l ?,ip′.
7 ?¨
52T£
ü:
(1) R…0 ln(sin )d = ?…22 ln2;
(2) R…0 sin 1?cos d = 2…ln2;
(3) R
…
20 sin2 ln(sin )d = …
4(
1
2 ?ln2);
(4) R10 ln(1+x)1+x2 dx = …8 ln2:
5
8£
ü??
T:
(1) 12(1? 1e) < R+10 e?x2dx < 1+ 12e;
(2) …2p2 < R10 dxp1?x4 < …2:
6